Difference between revisions of "User:Temperal/Introductory Proportion"
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| Line 4: | Line 4: | ||
xy=\frac{1}{k}\\ | xy=\frac{1}{k}\\ | ||
x=ky | x=ky | ||
| − | \end{cases} | + | \end{cases} </cmath> |
Find the possible values of '''k'''. | Find the possible values of '''k'''. | ||
==Solution== | ==Solution== | ||
{{incomplete|solution}} | {{incomplete|solution}} | ||
| − | If <math>x=\frac{1} {20}</math>, then <math> | + | If <math>x=\frac{1} {20}</math>, then <math> \frac{y} {20} = \frac{1} {k}</math>. |
Revision as of 11:55, 22 September 2007
Problem
Suppose 
is either x or y in the following system:
![\[\begin{cases} xy=\frac{1}{k}\\ x=ky \end{cases}\]](http://latex.artofproblemsolving.com/4/8/f/48f37af559f7c66fe3ccb3fb9b0e6c16b3fec444.png)
Find the possible values of k.
Solution
Template:Incomplete
If 
, then 
.
