1956 AHSME Problems/Problem 22

Problem 22

Jones covered a distance of $50$ miles on his first trip. On a later trip he traveled $300$ miles while going three times as fast. His new time compared with the old time was:

$\textbf{(A)}\ \text{three times as much} \qquad \textbf{(B)}\ \text{twice as much} \qquad \textbf{(C)}\ \text{the same} \\ \textbf{(D)}\ \text{half as much} \qquad \textbf{(E)}\ \text{a third as much}$

Solution

WLOG Jones travels at $50$ miles per hour. Then, it took him $1$ hour to travel $50$ miles at $50$ miles per hour.

On his second trip, he travels $300$ miles at $150$ miles per hour, which takes $\boxed{\textbf{(B)}\ \text{twice as much}}$ time as before.

~coolmath34

1956 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 21	Followed by Problem 23
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1956 AHSME Problems/Problem 22

Problem 22

Solution

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