Sums with twists

by sonone, Apr 11, 2020, 12:47 PM

I am going to find a general formula for sums like this: $$1(a)+2(ar)+3(ar^2)+\cdots $$Where $|r|<1$.
Let's call the sum $S$. The troublesome part of this sum is the $1,2,3,\cdots$. To get rid of the coefficients, let's multiply $S$ by $r$:
\begin{align*}
S&=1(a)+2(ar)+3(ar^2)+4(ar^3)+\cdots\\ \vspace{55pt}
Sr&= \phantom{1(a).....}1(ar)+2(ar^2)+3(ar^3)+\cdots
\end{align*}Now let's eliminate some terms by computing $S-Sr$:\begin{align*}
S&=1(a)+2(ar)+3(ar^2)+4(ar^3)+\cdots\\ 
Sr&= \phantom{1(a).....}1(ar)+2(ar^2)+3(ar^3)+\cdots\\ \hline
S-Sr&=~~a~~+~~ar~~~+~~ar^2~~+~~ar^3~~+~~\cdots
\end{align*}Now we can apply the infinite Geometric series formula getting $$S-Sr=\dfrac{a}{1-r}.$$Solving for $S$, we get \begin{align*}
S-Sr&=\dfrac{a}{1-r}\\
S(1-r)&=\dfrac{a}{1-r}\\
S&=\dfrac{a}{(1-r)^2}\text{ or }\dfrac{a}{1-2r+r^2}.
\end{align*}
Now try to solve these:
$\bullet ~~$ Calculate: $$\dfrac{1}{2}+\dfrac{1}{2}+\dfrac{3}8+\cdots+\dfrac{n}{2^n}+\cdots.$$$\bullet ~~$ Calculate: $$\dfrac{1}{3}+\dfrac{1}{3}+\dfrac{1}{4}+\cdots+\dfrac{n}{3\cdot 2^{n-1}}+\cdots.$$$\star ~~$ What is the expected number of rolls it takes to roll a $3$ on a fair $6$-sided die?
This post has been edited 1 time. Last edited by sonone, Apr 11, 2020, 12:47 PM
Reason: missing period not inserted

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Old material is mostly Asymptote, new material is calculator programming

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  • I still exist as well.

    by G.G.Otto, Aug 11, 2023, 2:44 AM

  • hello I'm still here lol

    by player01, Aug 6, 2022, 6:24 PM

  • [REVIVAL] I will start posting more calculator relating posts very soon. Even though school has been busy, I have been programming my calculators a decent amount, so I have a lot to share...

    by sonone, Feb 18, 2022, 10:29 PM

  • wow its been like 2.5 years since geo class

    by pieMax2713, Feb 4, 2022, 8:38 PM

  • @violin21, I've been very busy with school lately and haven't been able to add another lesson. I will when i get a free moment

    by sonone, Aug 19, 2021, 12:45 AM

  • ORZ CODER

    by samrocksnature, Aug 9, 2021, 9:57 PM

  • Could you make more Asymptote lessons on your "How to do Asymptote" blog?

    by violin21, Aug 9, 2021, 7:26 PM

  • You can take it, just C&P the CSS into your CSS area

    by sonone, Apr 17, 2021, 10:08 PM

  • how can we take the CSS if we have permission to not take it?

    by GoogleNebula, Apr 17, 2021, 5:22 PM

  • That is awesome!

    by sonone, Apr 15, 2021, 10:09 PM

  • I modified your dodecahedron and got:
    [asy]
    import three;
    import solids;
    size(300);
    currentprojection=orthographic(0,1.3,1.2);
    light(0,5,10);

    real phi=(sqrt(6)+1)/3;
    real g=(phi-1)/2;
    real s=1/2;
    real a=sqrt(1-phi*phi/4-g*g)+phi/2;

    triple[] d;
    d[0]=(phi

    by Andrew2019, Mar 26, 2021, 12:15 AM

  • Not too many, just changing the color here and there. I really like your CSS!

    by sonone, Feb 2, 2021, 10:35 AM

  • Nice!

    I see you're making changes to the CSS. :)

    by G.G.Otto, Feb 1, 2021, 9:26 PM

  • I'm learning Java now!

    by sonone, Feb 1, 2021, 5:56 PM

  • And I took part of it from CaptainFlint and then added a ton of modifications. ;)

    by G.G.Otto, Dec 1, 2020, 8:56 AM

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