Algebraic Manipulation

by Darealzolt, Apr 30, 2025, 1:25 PM

Find the number of pairs of real numbers $a, b, c$ that satisfy the equation $a^4 + b^4 + c^4 + 1 = 4abc$.

Very tasteful inequality

by tom-nowy, Apr 30, 2025, 10:47 AM

Let $a,b,c \in (-1,1)$. Prove that $$(a+b+c)^2+3>(ab+bc+ca)^2+3(abc)^2.$$

Physical or online

by wimpykid, Apr 30, 2025, 6:49 AM

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BrUMO 2025 Team Round Problem 13

by lpieleanu, Apr 27, 2025, 11:18 PM

Let $\omega$ be a circle, and let a line $\ell$ intersect $\omega$ at two points, $P$ and $Q.$ Circles $\omega_1$ and $\omega_2$ are internally tangent to $\omega$ at points $X$ and $Y,$ respectively, and both are tangent to $\ell$ at a common point $D.$ Similarly, circles $\omega_3$ and $\omega_4$ are externally tangent to $\omega$ at $X$ and $Y,$ respectively, and are tangent to $\ell$ at points $E$ and $F,$ respectively.

Given that the radius of $\omega$ is $13,$ the segment $\overline{PQ}$ has a length of $24,$ and $YD=YE,$ find the length of segment $\overline{YF}.$
This post has been edited 1 time. Last edited by lpieleanu, Apr 27, 2025, 11:44 PM
Reason: forgot \overline on last segment

Sequence

by lgx57, Apr 27, 2025, 12:56 PM

$a_1=1,a_{n+1}=a_n+\frac{1}{a_n}$. Find the general term of $\{a_n\}$.

đề hsg toán

by akquysimpgenyabikho, Apr 27, 2025, 6:52 AM

Inequalities

by sqing, Apr 26, 2025, 12:58 PM

Let $x\in(-1,1). $ Prove that
$$  \dfrac{1}{\sqrt{1-x^2}} + \dfrac{1}{2+ x^2}  \geq  \dfrac{3}{2}$$$$ \dfrac{2}{\sqrt{1-x^2}} + \dfrac{1}{1+x^2} \geq 3$$

Three variables inequality

by Headhunter, Apr 20, 2025, 6:58 AM

$\forall a\in R$ ,$~\forall b\in R$ ,$~\forall c \in R$
Prove that at least one of $(a-b)^{2}$, $(b-c)^{2}$, $(c-a)^{2}$ is not greater than $\frac{a^{2}+b^{2}+c^{2}}{2}$.

I assume that all are greater than it, but can't go more.

Inequlities

by sqing, Jul 19, 2024, 12:48 PM

Let $ a,b,c\geq 0 $ and $ a^2+ab+bc+ca=3 .$ Prove that$$\frac{1}{1+a^2}+ \frac{1}{1+b^2}+  \frac{1}{1+c^2} \geq \frac{3}{2}$$$$\frac{1}{1+a^2}+ \frac{1}{1+b^2}+ \frac{1}{1+c^2}-bc \geq -\frac{3}{2}$$
This post has been edited 1 time. Last edited by sqing, Jul 19, 2024, 12:59 PM

Inequalities

by sqing, Jul 12, 2024, 10:41 AM

Let $a,b,c> 0$ and $\frac{1}{a}+\frac{1}{b}+\frac{1}{c}=1.$ Prove that
$$  (1-abc) (1-a)(1-b)(1-c)  \ge 208 $$$$ (1+abc) (1-a)(1-b)(1-c)  \le -224 $$$$(1+a^2b^2c^2) (1-a)(1-b)(1-c)  \le -5840 $$

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