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The Spirit of Ramanujan

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AoPS instructor David Patrick will discuss the Spirit of Ramanujan Talent Initiative. We will discuss Ramanujan's life and some of the mathematics that he produced, and we will discuss the SoR program and how to apply. AoPS is a partner of SoR in 2020-21. We will be joined by Professor Ken Ono of the University of Virginia, who is the Director of the SoR program and was an associate producer and mathematical consultant for The Man Who Knew Infinity, a feature film about Ramanujan starring Dev Patel.

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Facilitator: Dave Patrick

DPatrick 2021-12-02 19:26:01
Welcome to the 2021-22 Spirit of Ramanujan Math Jam! We'll get started in about 5 minutes.
smileapple 2021-12-02 19:26:45
cool, is it about the movie or the organization/scholarship?
DPatrick 2021-12-02 19:27:07
We'll mention the movie, but it's mostly about Ramanujan himself, some of the math he did, and we'll talk about the scholarship program at the end.
medical_ordnance 2021-12-02 19:27:17
Let me guess DPatrick David Patrick?
DPatrick 2021-12-02 19:27:23
Yep, that's me!
peterguo 2021-12-02 19:28:14
why dont you host the math jam on his birthday
peterguo 2021-12-02 19:28:14
its in like less than a month
DPatrick 2021-12-02 19:28:27
True...I think there will be other events around his birthday though!
DPatrick 2021-12-02 19:28:40
This was a good night on our schedule and on our special guest's schedule.
Kaito471 2021-12-02 19:29:00
Special guest?
suvamkonar 2021-12-02 19:29:00
who's the guest?
DPatrick 2021-12-02 19:29:08
You'll find out in a minute or two!
smileapple 2021-12-02 19:29:45
ken ono?
ThinkThink 2021-12-02 19:29:45
Let me guess, the guest is KenOno?
DPatrick 2021-12-02 19:29:59
Good deducing. I'll introduce him properly in a minute or so.
DPatrick 2021-12-02 19:30:14
Time to get started!
DPatrick 2021-12-02 19:30:20
Welcome to the 2021-22 Spirit of Ramanujan Math Jam!
DPatrick 2021-12-02 19:30:29
https://spiritoframanujan.com/wp-content/uploads/2018/09/Ramanujan_LOGO.png
DPatrick 2021-12-02 19:30:40
I'm Dave Patrick, and I'll be leading our discussion tonight. Many of you know me from around AoPS: I've taught dozens of AoPS classes over the past 17 years, and I've written or co-written a few of our textbooks.
DPatrick 2021-12-02 19:30:56
I'm pleased to have a very special guest here with us tonight. Ken Ono (KenOno) is the Thomas Jefferson Professor and Chair of the Department of Mathematics at the University of Virginia.
KenOno 2021-12-02 19:31:05
Hi everyone!
DPatrick 2021-12-02 19:31:14
Ken is also the Director of the "Spirit of Ramanujan" project, with which AoPS is a partner, and which we'll be talking about tonight.
KenOno 2021-12-02 19:31:34
So happy to be here in AoPs world.
DPatrick 2021-12-02 19:31:41
Before we get started I would like to take a moment to explain our virtual classroom procedures to those who have not previously participated in a Math Jam or one of our online classes.
DPatrick 2021-12-02 19:31:59
The classroom is moderated, meaning that students can type into the classroom, but these comments will not go directly into the room. These comments go to the moderators, who may choose to share your comments with the room, or to respond to them privately if we can.
DPatrick 2021-12-02 19:32:14
This helps keep the discussion organized and on track. This also means that only well-written comments are likely to be dropped into the classroom, so please take time writing responses that are complete and easy to read.
DPatrick 2021-12-02 19:32:26
Today we also have a teaching assistant: Tudor Sarpe (Snakes).
DPatrick 2021-12-02 19:32:43
Tudor first joined AoPS in 2015, though he has been browsing the AoPS contest collections and forums since 2012. Tudor is from Moldova, a small country in Eastern Europe that too few people know about. During High School, he has been highly involved in mathematics and science olympiads. He has won top places at national maths, biology, physics and chemistry olympiads, has a couple bronze medals from the Balkan Mathematical Olympiad, and has been on the IMO team.
Snakes 2021-12-02 19:32:52
Hi, everyone :)
DPatrick 2021-12-02 19:33:08
Snakes is here to try to answer any questions that you have, and Ken and I will also be answering questions at the end. We may have a lot of students here tonight, so please be patient! We may not be able to get to every question.
DPatrick 2021-12-02 19:33:24
Tonight, we're going to talk about the life and mathematics of Srinivasa Ramanujan.
DPatrick 2021-12-02 19:33:29
https://spiritoframanujan.com/wp-content/uploads/2018/09/postage-copy.jpg
DPatrick 2021-12-02 19:33:54
And we'll be talking about a project called "Spirit of Ramanujan" that Ken Ono founded, the goal of which is to help find and nurture future mathematical and scientific talent.
DPatrick 2021-12-02 19:34:07
But first, let's talk about Ramanujan himself.
DPatrick 2021-12-02 19:34:13
Anybody know about him?
CalvinAndDobbs 2021-12-02 19:34:41
My dad said he could do complex math problems in his head and he didn't go to a universinty or anything
Ladka13 2021-12-02 19:34:41
the most famous Indian mathematician.
aquagold 2021-12-02 19:34:41
yes he found a fraction that is better than 22/7 for pi
srihaas 2021-12-02 19:34:41
yes, he is a famous indian mathmaticean
ZJ42 2021-12-02 19:34:41
I know the story about the taxi
Kaito471 2021-12-02 19:34:48
He only lived for 33 years :( According to the post stamp
P3Tan 2021-12-02 19:34:48
He was born in 1887 and died in 1920
KenOno 2021-12-02 19:35:09
Lots of knowledgeable folks out tonight.
DPatrick 2021-12-02 19:35:11
As you may know, there was recently (2015) a motion picture about Ramanujan's life titled The Man Who Knew Infinity, starring Dev Patel and Jeremy Irons. The film is based on a biography of the same title written in 1991 by Robert Kanigel.
DPatrick 2021-12-02 19:35:17
Our guest Ken Ono was one of the mathematical consultants on the film.
DPatrick 2021-12-02 19:35:21
Did anybody here see the movie?
krishiam 2021-12-02 19:35:44
I did it was good
Jc426 2021-12-02 19:35:44
I saw the trailer :P
ZJ42 2021-12-02 19:35:44
I didn't but now I want to :)
dBIT 2021-12-02 19:35:49
Yes I have seen the movie
Printrbot 2021-12-02 19:35:49
No, but I want to now!
DPatrick 2021-12-02 19:35:56
Unfortunately as of right now it does not appear to be available for free on any streaming service in the U.S. :(

It is available for rent for $2.99 on a bunch of different sites.
DPatrick 2021-12-02 19:36:14
Ramanujan was born in Erode, India in 1887. He grew up relatively poor and worked as a clerk. But from an early age he clearly had a love and aptitude for mathematics.
DPatrick 2021-12-02 19:36:30
By age 11 he was the mathematical equal of university students who were boarding in his family home. He was able to continue his advanced study of math by reading as many books as he could get his hands on. He also, around age 15, discovered on his own how to solve a quartic equation.
DPatrick 2021-12-02 19:36:46
(We'll talk more about this in a few minutes when we start talking about Ramanujan's mathematical achievements. And don't worry if you don't know what "quartic equation" means -- I'll explain that too!)
Ladka13 2021-12-02 19:37:03
but how did he get so good with no training. he can't just wake up and know everything
DPatrick 2021-12-02 19:37:23
Well, he was fortunate in that he had access to lots of books. And he was a really hard worker!
DPatrick 2021-12-02 19:37:41
A particular book that furthered his study was A Synopsis of Elementary Results in Pure and Applied Mathematics by G.S. Carr, that Ramanujan obtained in 1903 at age 16. This book was written in 1886. It contained over 5000 theorems and was an attempt to summarize all the "basic" mathematics known at the time. (Last time I checked, you can find it in Google Books!) Ramanujan read and studied it in great detail and it formed the foundation of his mathematical thought.
DPatrick 2021-12-02 19:38:09
Ramanujan spent so much time on mathematics that he generally did poorly in other subjects in school, and as such failed to graduate from university. He unfortunately also suffered from various illness (much of which were probably made worse due to poverty, and to the lack of "modern" medicine in India at the time), which also interfered with his formal studies.
srihaas 2021-12-02 19:38:21
did he write any books?
DPatrick 2021-12-02 19:38:35
Indeed he wrote a lot!
DPatrick 2021-12-02 19:38:51
He started publishing papers containing his original work in India, small articles at first, but eventually his first "full" paper titled "Some Properties of Bernoulli's Numbers" in 1911 in the Journal of the Indian Mathematical Society. This paper, in particular, started establishing Ramanujan's reputation as a mathematical genius in India.
DPatrick 2021-12-02 19:39:11
But, even though his mathematical talent was becoming acknowledged within India, he had trouble finding employment as a mathematician because of his lack of a formal university degree. Instead, he had to work as a clerk for low pay and rely on the additional financial support of others in the Indian mathematics community.
DPatrick 2021-12-02 19:39:25
Anybody know what changed for him in 1913?
DPatrick 2021-12-02 19:39:34
(If you saw the movie you probably know)
HobbsClass 2021-12-02 19:39:56
He wrote a letter to Hardy
Ladka13 2021-12-02 19:39:56
he meta famous mathematician I believe
Kaito471 2021-12-02 19:39:56
Did he gain an opportunity of some sort?
ZJ42 2021-12-02 19:39:56
He met Hardy
srihaas 2021-12-02 19:40:00
he met G.H Hardy? (did not see the movie)
Arcticturn 2021-12-02 19:40:00
He worked with GH hardy
DPatrick 2021-12-02 19:40:09
Right! A major turning point in Ramanujan's life was his writing a letter to the prominent British mathematician G. H. Hardy in January 1913. His letter began:
DPatrick 2021-12-02 19:40:14
I have had no university education but I have undergone the ordinary school course. After leaving school I have been employing the spare time at my disposal to work at mathematics. I have not trodden through the conventional regular course which is followed in a university course, but I am striking out a new path for myself. I have made a special investigation of divergent series in general and the results I get are termed by the local mathematicians as 'startling'.
DPatrick 2021-12-02 19:40:28
Enclosed with the letter was pages of Ramanujan's work -- he was hoping that Hardy would be able to mentor him and help him get his work improved and published to the wider world. He had written to other mathematicians in Britain, who had basically ignored his letters.
DPatrick 2021-12-02 19:40:42
But Hardy took the letter seriously. Although a lot of the work was unproved and was poorly written, it was clear to Hardy that there was a lot of really good math in Ramanujan's letter! Hardy started a professional relationship with Ramanujan and was able to provide financial support.
KenOno 2021-12-02 19:40:45
David, you type really fast!!!
DPatrick 2021-12-02 19:40:59
Magic. :)
ZJ42 2021-12-02 19:41:10
cntrl C/V?
DPatrick 2021-12-02 19:41:19
It is possible I may have written some of this beforehand...
DPatrick 2021-12-02 19:41:28
Anyway...In 1914, Hardy arranged for Ramanujan to be able to travel and visit Trinity College at Cambridge University in England.
DPatrick 2021-12-02 19:41:44
Any idea how long it took Ramanujan to travel from India to London? Remember, this was slightly over 100 years ago!
awesomeaadharsa 2021-12-02 19:42:09
a month or 2
peterguo 2021-12-02 19:42:09
like a few weeks possibly
plantLover 2021-12-02 19:42:09
a month?
CerealTurtle 2021-12-02 19:42:09
3 weeks?
QueenRaven337 2021-12-02 19:42:09
a month? or maybe 2 weeks?
Arcticturn 2021-12-02 19:42:09
3 weeks?
DPatrick 2021-12-02 19:42:19
These are all pretty close. It took 27 days.
DPatrick 2021-12-02 19:42:27
Ramanujan left India on March 17, 1914 by boat, and arrived in London on April 14.
DPatrick 2021-12-02 19:42:42
This began a 5-year collaboration with Hardy that produced many important mathematical results. Also, Ramanujan was finally able to finish his formal education, and graduated from Cambridge with the equivalent of a Ph.D. in 1916.
Arcticturn 2021-12-02 19:43:01
in 2 years?!
DPatrick 2021-12-02 19:43:19
He had most of the knowledge already -- what the university did mostly was just make the degree official.
DPatrick 2021-12-02 19:43:38
With financial stability and a group of peers that respected his work, Ramanujan was able to professionally thrive in England. Many honors followed including perhaps the most prestigious: in 1918 he was elected a Fellow of the Royal Society, probably the highest honor that can be given for science in Britain. Ramanujan was only the second Indian so elected, and one of the youngest at age 31.
Morgan456 2021-12-02 19:43:46
Did he ever go back to India?
DPatrick 2021-12-02 19:44:11
Yes: In early 1919, World War I was over so (now age 31) he decided to return to his native India, with his reputation firmly established and his financial situation stable. The hope was that he would continue his career as a full member of India's mathematical community.
KenOno 2021-12-02 19:44:14
And we are still trying to figure out stuff in 3 notebooks he left behind. I've held them in my hands.
DPatrick 2021-12-02 19:44:32
Sadly, upon returning to India, he almost immediately fell into poor health, and after about a year, he died on April 26, 1920, at an age of only 32.
ChrisalonaLiverspur 2021-12-02 19:44:51
:(
srihaas 2021-12-02 19:44:51
he had so much to live for :(
dBIT 2021-12-02 19:45:03
I got the opportunity ti visit the Ramanujan Museum in Chennai. Heartwarming to see photos and his letters displayed
DPatrick 2021-12-02 19:45:09
If you're interested in reading a more thorough biography of Ramanujan, there is one on the "History of Mathematics" site maintained by the University of St. Andrews, at
http://www-history.mcs.st-and.ac.uk/Biographies/Ramanujan.html
The quotes that I've used above are from this page.
KenOno 2021-12-02 19:45:13
Nice dBit.
DPatrick 2021-12-02 19:45:29
As an aside, this website is a great resource: it has biographies of over 3,000 mathematicians spanning over 35 centuries, from Ahmes (1680-1620 BC) to Mirzakhani (1977-2017), and includes many living mathematicians as well.
DPatrick 2021-12-02 19:45:50
Now let's talk about some the mathematics that Ramanujan studied.
DPatrick 2021-12-02 19:46:07
Ramanujan did a lot of mathematics in his relatively short life, and a great deal of it was quite advanced. Way too advanced for us to talk about here! But there are some objects of his study that we can discuss tonight.
DPatrick 2021-12-02 19:46:16
First, I mentioned earlier that one of Ramanujan's earliest advanced studies was, in his early teen years, his study of solutions to quartic and quintic equations.
DPatrick 2021-12-02 19:46:26
To start, many of you already know how to solve quadratic equations, which is an equation involving a polynomial of degree 2. In particular, how can we solve $ax^2 + bx + c = 0$?
karthic7073 2021-12-02 19:47:01
quadratic formula
PWT 2021-12-02 19:47:01
quadratic formula
RedFireTruck 2021-12-02 19:47:01
quadratic formula :O
tacowizard 2021-12-02 19:47:01
Comeplete the square
QueenRaven337 2021-12-02 19:47:01
Factoring, complete the square, or quadratic formula
ChrisalonaLiverspur 2021-12-02 19:47:01
quadratic formula? complete the square? factor?
DPatrick 2021-12-02 19:47:13
Certainly there are many different methods!
DPatrick 2021-12-02 19:47:25
But one that always works is to use the well-known quadratic formula: $$x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$$
DPatrick 2021-12-02 19:47:54
It is pretty straightforward to prove that this always works, using basic algebra. (We prove it in AoPS's Introduction to Algebra textbook and classes.)
HonestCat 2021-12-02 19:48:01
I prefer completing the square
Ladka13 2021-12-02 19:48:01
completing the square is so underrated
DPatrick 2021-12-02 19:48:05
I agree!
DPatrick 2021-12-02 19:48:13
The next step up is solving the cubic equation $ax^3 + bx^2 + cx + d = 0$.
QueenRaven337 2021-12-02 19:48:23
But, those types of formulas has to be pretty long if applied to cubic, quartic, quintic etc.
DPatrick 2021-12-02 19:48:32
Indeed -- there is a formula for solving this as well, but it's a lot more complicated.
KenOno 2021-12-02 19:48:37
Nice QueenRaven337.
DPatrick 2021-12-02 19:48:42
If we set



$$\begin{array}{rcl}

p &=& -\frac{b}{3a} \\

q &=& p^3 + \frac{bc-3ad}{6a^2} \\

r &=& \frac{c}{3a}

\end{array}$$
DPatrick 2021-12-02 19:48:53
then we get
$$x = \sqrt[3]{q + \sqrt{q^2 + (r-p^2)^3}} + \sqrt[3]{q - \sqrt{q^2 + (r-p^2)^3}} + p.$$
vedp4008 2021-12-02 19:49:08
wow
ZJ42 2021-12-02 19:49:08
woah
DPatrick 2021-12-02 19:49:16
Yeah. Most people don't bother to ever learn this formula nowadays: it's way too complicated to accurately memorize. (I certainly don't have it memorized -- I looked it up.)
pikapika007 2021-12-02 19:49:34
how would you go about proving it?
DPatrick 2021-12-02 19:49:46
It's pretty complicated -- way too complicated to quickly discuss tonight I'm afraid.
DPatrick 2021-12-02 19:50:02
But it's been around a while. This formula, and other similar formulas for solving cubics, were discovered in the 1500s. Ramanujan would have learned this in his early teens.
DPatrick 2021-12-02 19:50:24
What Ramanujan then undertook, and eventually successfully solved himself, was solving the quartic equation $ax^4 + bx^3 + cx^2 + dx + e = 0$.
srihaas 2021-12-02 19:50:44
oh no...
Coldapple 2021-12-02 19:50:44
wow
DPatrick 2021-12-02 19:50:54
I'm not even going to write the formula down -- it would take way way too much space.
DPatrick 2021-12-02 19:51:06
You can find it here if you're curious: https://commons.wikimedia.org/wiki/File:Quartic_Formula.svg
DPatrick 2021-12-02 19:51:15
(Basically just look for it on Wikipedia)
DPatrick 2021-12-02 19:51:38
It's possible that Ramanujan thought that he had discovered something new. He almost certainly didn't know that the quartic had also been solved in the 1500s.
DPatrick 2021-12-02 19:51:50
But it is an extremely complicated formula, and it's amazing that Ramanujan was able to discover it, essentially working on his own, at age 15.
Printrbot 2021-12-02 19:51:56
You wern't kidding about taking too much space
DPatrick 2021-12-02 19:52:04
I know, right?
peterguo 2021-12-02 19:52:12
would the quintic be even longer
DPatrick 2021-12-02 19:52:25
Yeah, Ramanujan attempted to solve the quintic equation:
$$ ax^5 + bx^4 + cx^3 + dx^2 + ex + f = 0 $$
mop 2021-12-02 19:52:40
Quintic doesn't exist
srihaas 2021-12-02 19:52:40
there is no quintic formula
Arcticturn 2021-12-02 19:52:40
I don't think you can solve the quintic equation...
mop 2021-12-02 19:52:40
The quintic formula doesn't exist.
DPatrick 2021-12-02 19:52:47
He did not have success.
DPatrick 2021-12-02 19:52:55
That's because in the early 1800s, the mathematicians Ruffini and Abel actually proved that a solution was impossible! That is, there is no possible formula (no matter how complicated) that can be used to plug in the coefficients of a quintic and output a solution. (Ruffini first came up with the result in 1799, but his proof was incomplete. Abel completed the proof in 1824.)
DPatrick 2021-12-02 19:53:19
A little later in the 1800s, the mathematician Galois developed a new branch of mathematics (that today is called Galois theory) that provided a more elegant proof that there is no formula to solve the quintic. It's part of a branch of mathematics called field theory, which you typically first learn about in an undergraduate abstract algebra course. (Or in AoPS's Group Theory course!)
DPatrick 2021-12-02 19:53:43
But Ramanujan probably didn't know any of this at the time. And more importantly, he didn't let his lack of success in this particular problem deter him from his continued pursuit of mathematics.
DPatrick 2021-12-02 19:54:00
That's a good lesson for us all -- a lot of problems are hard. We may not be able to solve them. But that shouldn't deter us from trying! We often learn a lot from our attempts to solve problems, even if we don't come up with the solution we want.
DPatrick 2021-12-02 19:54:37
So on to something else...someone mentioned a taxi a little bit eariler...
KenOno 2021-12-02 19:54:40
I actually took 20 years to solve a problem.
DPatrick 2021-12-02 19:55:01
Indeed, that's not all that unusual for professional mathematicians!
ZJ42 2021-12-02 19:55:13
I mentioned the taxi :P
DPatrick 2021-12-02 19:55:20
One of the most famous anecdotes regarding Ramanujan occurred when Hardy was visiting Ramanujan in the hospital during one of his many illnesses.
Kaito471 2021-12-02 19:55:31
Wasn't there an interesting number on the top of a taxi or something that made Ramanujan think?
dBIT 2021-12-02 19:55:45
yes thr taxicab numbers
DPatrick 2021-12-02 19:55:47
That's right -- Hardy recalled telling Ramanujan that he traveled to the hospital in taxicab number $1729$, and was disappointed that the cab number was so dull. Ramanujan immediately replied that on the contrary, $1729$ was a very interesting number. Do you know why?
HonestCat 2021-12-02 19:56:24
Sum of 2 cubes in 2 different ways
SparklyFlowers 2021-12-02 19:56:24
it's the sum of two cubes or smething
karthic7073 2021-12-02 19:56:24
it was the smallest number that can be written as the sum of two cubes in two different ways
DPatrick 2021-12-02 19:56:36
$1729$ is the smallest number that can be written as a sum of two positive cubes in two different ways! Can you find them?
KenOno 2021-12-02 19:56:47
Nice guys! It is also my license plate number in Virginia.
srihaas 2021-12-02 19:57:05
1729 = 12^3 +1^3 = 10^3 + 9^3
HonestCat 2021-12-02 19:57:05
10^3+9^3 and 12^3+1^3
Lionking212 2021-12-02 19:57:05
1729=$12^3+1^3=10^3+9^3$
karthic7073 2021-12-02 19:57:05
10^3+9^3 and 12^3+1^3
twwig 2021-12-02 19:57:05
1000 and 729 is one
mop 2021-12-02 19:57:05
$1^3+12^3=10^3+9^3=1729$
QueenRaven337 2021-12-02 19:57:05
1000 + 729 and 1728 + 1
DPatrick 2021-12-02 19:57:16
Nice!
DPatrick 2021-12-02 19:57:20
$1729 = 1^3 + 12^3 = 1 + 1728$



$1729 = 9^3 + 10^3 = 729 + 1000$
DPatrick 2021-12-02 19:57:39
For this reason, $1729$ is called the 2nd taxicab number. It's also sometimes called the Hardy-Ramanujan number.
sdash314 2021-12-02 19:57:51
What's the first?
DPatrick 2021-12-02 19:57:56
The first is $2 = 1^3 + 1^3$. It's the smallest number that can be written as a sum of two positive cubes in one way.
DPatrick 2021-12-02 19:58:10
Then, the 3rd taxicab number is the smallest number that can be written as a sum of two positive cubes in three different ways. Any guess as to how big it is? (How many digits do you think it has?)
boing123 2021-12-02 19:58:44
9?
Coldapple 2021-12-02 19:58:44
10
HonestCat 2021-12-02 19:58:44
8
krithikrokcs 2021-12-02 19:58:44
9
srihaas 2021-12-02 19:58:44
7 digits
HonestCat 2021-12-02 19:58:44
x*10^8 or something
arjken 2021-12-02 19:58:44
Maybe 7 digits?
DPatrick 2021-12-02 19:58:50
You're in the right ballpark.
DPatrick 2021-12-02 19:58:56
It's the 8-digit number $87{,}539{,}319$, which is $167^3 + 436^3 = 228^3 + 423^3 = 255^3 + 414^3$.
DPatrick 2021-12-02 19:59:03
It's likely that this was first discovered as recently as 1957.
P3Tan 2021-12-02 19:59:09
so the 4th would be the smallest number that can be written as a sum of two positive cubes in 4 ways?
DPatrick 2021-12-02 19:59:14
Exactly!
DPatrick 2021-12-02 19:59:21
And more generally, the $n$th taxicab number is the smallest positive integer that can be written as a sum of two positive cubes in $n$ different ways.
algebrakitty318 2021-12-02 19:59:31
What about the next one? Was that found?
karthic7073 2021-12-02 19:59:37
whats the highest taxi cab number found?
DPatrick 2021-12-02 19:59:50
As of right now, the first 6 taxicab numbers are known:

$2$

$1729$

$87539319$

$6963472309248$

$48988659276962496$

$24153319581254312065344$
Lionking212 2021-12-02 19:59:59
how do u calculate the nth taxikab number?
P3Tan 2021-12-02 19:59:59
what is the 10th?
DPatrick 2021-12-02 20:00:04
Nobody knows! (Yet!)
ZJ42 2021-12-02 20:00:13
computers could probably find more, right?
algebrakitty318 2021-12-02 20:00:13
Those are some big numbers
DPatrick 2021-12-02 20:00:24
Yeah...these are big numbers even for computers.
DPatrick 2021-12-02 20:00:40
The 6th taxicab number was only discovered by computer search in 2008.
peterguo 2021-12-02 20:00:57
how many digits do you think the seventh taxicab number would have
KenOno 2021-12-02 20:00:59
Great questions....This is about elliptic curves...and is closely related to the $1 million dollar prize problem.
KenOno 2021-12-02 20:01:11
Birch and Swinnerton-Dyer Conjecture.
DPatrick 2021-12-02 20:01:17
It is known that $24885189317885898975235988544$ can be written as a sum of two perfect cubes in $7$ different ways. So the 7th taxicab number is at most this number.
DPatrick 2021-12-02 20:01:23
But we don't know if this is actually the 7th taxicab number, because there might be a smaller number that works that we haven't found yet.
DPatrick 2021-12-02 20:01:51
And as Ken mentions, this is not just fun and games. This is tied to some really important unanswered questions in mathematics!
DPatrick 2021-12-02 20:02:14
Just recently in 2015, our guest Ken Ono and my AoPS colleague Sarah Trebat-Leder wrote a paper titled The 1729 K3 Surface which tied Ramanujan's observation about the number 1729 to some important curves and surfaces in the modern field of algebraic geometry.
KenOno 2021-12-02 20:02:32
And String theory...and quantum gravity.
DPatrick 2021-12-02 20:02:52
Mathematics is connected in so many interesting and mysterious ways.
DPatrick 2021-12-02 20:03:07
One more fun note about taxicab numbers: How many people here are fans of the TV show Futurama?
Lionking212 2021-12-02 20:03:34
me!!
DPatrick 2021-12-02 20:03:52
It's a somewhat older show by the same people that created The Simpsons.
DPatrick 2021-12-02 20:04:01
Apparently the creators of Futurama are big fans of taxicab numbers.
DPatrick 2021-12-02 20:04:12
In particular, the number $1729$ is hidden in several episodes. It's the registration number of the Planet Express ship on the show, for one thing.
DPatrick 2021-12-02 20:04:19
http://mathworld.wolfram.com/images/gifs/1729Futurama.jpg
DPatrick 2021-12-02 20:04:24
Image from mathworld.wolfram.com
DPatrick 2021-12-02 20:04:35
And in one scene someone hails a taxi. Can you make out the number on the cab's roof?
DPatrick 2021-12-02 20:04:39
https://i.kinja-img.com/gawker-media/image/upload/s--ya_coZqV--/c_fit,f_auto,fl_progressive,q_80,w_636/193a4a0f4oqtopng.png
DPatrick 2021-12-02 20:04:45
Image from Gawker Media
srihaas 2021-12-02 20:05:07
the 3rd taxicab number
karthic7073 2021-12-02 20:05:07
87539319
P3Tan 2021-12-02 20:05:07
87539319?
ZJ42 2021-12-02 20:05:07
87539319
twwig 2021-12-02 20:05:07
its the third taxicab nimber
Ladka13 2021-12-02 20:05:07
81539319
aquagold 2021-12-02 20:05:07
875399319
DPatrick 2021-12-02 20:05:12
It's hard to make out, but it's the 3rd taxicab number $87539319$.
DPatrick 2021-12-02 20:05:21
A little joke for those in the know.
DPatrick 2021-12-02 20:05:28
So, it may not surprise you to learn that Futurama's head writer did math contests in high school and has a degree in physics from Harvard!
mathcountisgreat 2021-12-02 20:05:43
Wow!
SparklyFlowers 2021-12-02 20:05:43
oo
DPatrick 2021-12-02 20:06:09
Finally for tonight's math, let's talk about partitions.
DPatrick 2021-12-02 20:06:23
A partition is a way a writing a positive integer as a sum of positive integers, where the order of the numbers in the sum doesn't matter.
DPatrick 2021-12-02 20:06:32
For example, all of the partitions of $3$ are:

$3$

$2+1$

$1+1+1$

(We don't list $1+2$ separately because the order of the terms doesn't matter. We also consider the "sum" $3$ as a partition of $3$.)
DPatrick 2021-12-02 20:06:42
One classic mathematical problem is to count the number of partitions of some number.
DPatrick 2021-12-02 20:06:49
For example, how many partitions of $6$ are there?
DPatrick 2021-12-02 20:07:14
To count them, we can try to list them.
plantLover 2021-12-02 20:07:48
6, 5+1, 4+2, 3+3
wamofan 2021-12-02 20:07:55
15, 24, 222, 114, 123, 1122, 1311, 121111, 111111
DPatrick 2021-12-02 20:08:10
Indeed, if we were careful and systematic about it, we could end up with the entire list:
DPatrick 2021-12-02 20:08:15
$6$

$5+1$

$4+2$

$4+1+1$

$3+3$

$3+2+1$

$3+1+1+1$

$2+2+2$

$2+2+1+1$

$2+1+1+1+1$

$1+1+1+1+1+1$
karthic7073 2021-12-02 20:08:27
11
HonestCat 2021-12-02 20:08:27
11?
Mkd20 2021-12-02 20:08:36
11
DPatrick 2021-12-02 20:08:42
Looks like there are 11 partitions of $6$.
peterguo 2021-12-02 20:08:50
is there a formula for this for a question like how many partitions of n are there
DPatrick 2021-12-02 20:08:56
An excellent question!
DPatrick 2021-12-02 20:09:05
Hardy and Ramanujan asked the same question!
DPatrick 2021-12-02 20:09:22
By brute force listing them, we could make a table of the number of partitions of the first 10 positive integers:
DPatrick 2021-12-02 20:09:27
$$\begin{array}{r|l}

n & \text{number of partitions of $n$} \\ \hline

1 & 1 \\

2 & 2 \\

3 & 3 \\

4 & 5 \\

5 & 7 \\

6 & 11 \\

7 & 15 \\

8 & 22 \\

9 & 30 \\

10 & 42

\end{array}$$
DPatrick 2021-12-02 20:09:40
The number of partitions of $n$ gets big pretty quick. For example, do you have a rough guess for the number of partitions of $100$?
Kaito471 2021-12-02 20:09:54
a lot.
DPatrick 2021-12-02 20:09:59
Indeed.
jason543 2021-12-02 20:10:17
over 190 million
DPatrick 2021-12-02 20:10:25
Yeah, it gets big quickly.
KenOno 2021-12-02 20:10:28
Nice guess.
DPatrick 2021-12-02 20:10:37
It turns out that there are $190{,}569{,}292$ different partitions of $100$.
smileapple 2021-12-02 20:10:54
is it exponential?
DPatrick 2021-12-02 20:11:02
It does seem to be growing super-fast.
DPatrick 2021-12-02 20:11:07
Ramanujan and Hardy wondered if they could come up with a formula for the number of partitions of $n$.
DPatrick 2021-12-02 20:11:21
They partially succeeded. They didn't come up with an exact formula, but they did come up with a formula that provides a good approximation.
DPatrick 2021-12-02 20:11:36
Their formula, today known as the Hardy-Ramanujan formula, is
$$p(n) \sim \frac{1}{4n\sqrt3}\exp\left(\pi\sqrt{\frac{2n}{3}}\right).$$
DPatrick 2021-12-02 20:11:47
In the formula $\exp(x)$ is an alternative way of writing $e^x$, where $e = 2.718281828\ldots$ is the Euler number.
DPatrick 2021-12-02 20:12:15
Using this formula, $p(100) \sim 199{,}280{,}893$. That's not too far off the exact answer that I showed you a moment ago.
SmartGroot 2021-12-02 20:12:24
what is the p at the beginning
DPatrick 2021-12-02 20:12:39
Sorry, I should have said that. $p(n)$ is our notation for the number of partitions of $n$.
Ladka13 2021-12-02 20:12:47
few hundred thousand off. not much
DPatrick 2021-12-02 20:13:09
The key is that the percentage error that the formula is off by gets smaller and smaller as $n$ grows large.
DPatrick 2021-12-02 20:13:19
For instance, we see that for $n=100$ the formula is a little less than $9$ million too high. That seems like a lot, but it's less than $5\%$ higher than the actual count.
DPatrick 2021-12-02 20:13:29
If we go to $n=1000$, the actual count is about $2.406 \cdot 10^{31}$ and the formula gives $2.440 \cdot 10^{31}$. The formula is only off by about $1.5\%$.
DPatrick 2021-12-02 20:13:41
At $n=10000$ the actual count is about $3.617 \cdot 10^{106}$ (that's more than a googol!) and the formula gives about $3.633 \cdot 10^{106}$. The formula is only off by about $0.5\%$.
JaiT 2021-12-02 20:13:46
and what is the ~ symbol
DPatrick 2021-12-02 20:13:58
That indicates that's it's not an exact formula -- it gives an approximation.
HonestCat 2021-12-02 20:14:02
Wait, how does pi show up here?
DPatrick 2021-12-02 20:14:08
That's a great question.
DPatrick 2021-12-02 20:14:23
It turns out that $\pi$ shows up in number theory a lot.
DPatrick 2021-12-02 20:14:38
As I said before...a lot of math is connected in very surprising ways!
DPatrick 2021-12-02 20:14:59
But you'll have to learn some more advanced math before we can explain exactly why this happens with $\pi$.
DPatrick 2021-12-02 20:15:09
Ramanujan studied partitions of integers quite a bit and produced a lot of results. There are a lot of open questions about partitions that are still studied to this day. Indeed, this is one of the areas of study of our guest Professor Ken Ono, and a lot of his work builds on work first started by Ramanujan nearly 100 years ago.
KenOno 2021-12-02 20:15:30
Yup...I still like to add and count.
DPatrick 2021-12-02 20:15:34
So that seems like a good note on which to transition into the Spirit of Ramanujan initiative. Here's an excerpt from an article called "Why Ramanujan Matters" written by Ken Ono and Robert Schneider:
DPatrick 2021-12-02 20:15:43
Ramanujan matters because he represents endless curiosity and untapped potential, which we all have to believe in to proceed in the sciences. Science usually advances on the work of thousands, over generations, fine-tuning and extending the scope of understanding. But from time to time, creative fireballs like Ramanujan burst onto the scene propelling human thought forward. Yet what if Ramanujan had not reached out to, or been taken seriously by Hardy? The loss of scientific understanding is something our modern world could not absorb. He matters because science matters: curiosity and creativity drive scientific inquiry.
DPatrick 2021-12-02 20:16:13
That's what the Spirit of Ramanujan (which I'm going to abbreviate as SoR from now on) is all about: finding young people who have the potential, with the right resources and mentorship, to contribute to humankind's knowledge like Ramanujan did.
DPatrick 2021-12-02 20:16:29
We at AoPS are pleased that Ken asked us to be a part of this search. SoR's goals are also part of AoPS's goals: to create a broader community of aspiring mathematicians and problems solvers, to make connections between people who might not otherwise have the opportunity to contact, and to provide resources via our website to all corners of the country and of the world.
KenOno 2021-12-02 20:16:48
We are pleased to partner with AoPS.
DPatrick 2021-12-02 20:16:51
Specifically, SoR provides two types of awards:
DPatrick 2021-12-02 20:16:55
The Templeton-Ramanujan Development Awards will provide books and monetary grants to offset the costs of online resources.
DPatrick 2021-12-02 20:17:02
The Templeton-Ramanujan Fellowships will provide monetary grants to offset the costs of enrolling in approved enrichment programs, such as summer camps.
KenOno 2021-12-02 20:17:06
Such as AoPS courses!
DPatrick 2021-12-02 20:17:25
In case you're wondering...the "Templeton" in these names is the Templeton World Charity Foundation, created by the late Sir John Templeton, and which is providing the funding for SoR.
KenOno 2021-12-02 20:17:36
We have now supported 66 people worldwide...from 14 countries.
DPatrick 2021-12-02 20:18:07
Indeed, 2021-22 is the 6th year of the program. About half of the students supported are from the U.S. and half from elsewhere in the world.
KenOno 2021-12-02 20:18:14
Two of our former winners this year won the Regeneron Science Talent Search...and also a Rhodes Scholarship.
DPatrick 2021-12-02 20:18:18
Basically, SoR is hoping to play to role for future Ramanujans that G. H. Hardy did for the actual Ramanujan: access to resources and mentorship to nurture future mathematical and scientific talent.
DPatrick 2021-12-02 20:18:41
To learn more about SoR, please visit the website spiritoframanujan.com. (Should be easy to remember, no?) The SoR website includes a link to the application page. You can also read brief bios of the previous winners on the website.
DPatrick 2021-12-02 20:19:02
Please note that although awards for the 2021-22 school year will be made on a rolling basis, you should apply by April 30, 2022 in order to guarantee full consideration.
KenOno 2021-12-02 20:19:23
In recent years we have offered scholarships to things like AoPS courses...Canada/USA MathCamp, PROMYS, etc...
DPatrick 2021-12-02 20:19:56
Yes, I believe that generally Ken and the foundation works with the award winners to tailor a program that's best for that person.
KenOno 2021-12-02 20:20:14
David is on our board...along with Fields medalist Manjul Bhargava...and others....
KenOno 2021-12-02 20:20:51
Yes, please apply. We seek enthusiastic creative minds...Especially if our support can make participation possible.
DPatrick 2021-12-02 20:20:57
...and Po-Shen Loh I believe, is that right?
KenOno 2021-12-02 20:21:27
Ah yes...How can I forget Po-Shen...
DPatrick 2021-12-02 20:21:39
Certainly a familiar name to many on AoPS!
P3Tan 2021-12-02 20:21:53
who is po shen?
DPatrick 2021-12-02 20:22:04
He is the leader of the US Team for the International Math Olympiad.
DPatrick 2021-12-02 20:22:08
(Among other things!)
DPatrick 2021-12-02 20:23:18
That's all we have for tonight...we can try to answer some questions for a little while if you have any. There's also lots of info on the SoR website, along with contact info if you'd like to follow up.
DPatrick 2021-12-02 20:23:26
spiritoframanujan.com
KenOno 2021-12-02 20:23:30
To repeat...please visit spiritoframanujan.com
DPatrick 2021-12-02 20:23:37
Can't repeat it enough! :)
DofL 2021-12-02 20:24:06
when is the optimal time to apply for SoR? what qualifications do we need for it?
DPatrick 2021-12-02 20:24:18
Anytime between now and April 30 will guarantee full consideration.
DPatrick 2021-12-02 20:24:25
The info you'll need to apply is on the website.
KenOno 2021-12-02 20:24:27
We have made awards to students as young as 8-9....
SmartGroot 2021-12-02 20:24:31
Oh KevinOno you face revealed!
DPatrick 2021-12-02 20:24:41
Yes, if you want to see what Ken looks like, go to the SoR website. :)
DPatrick 2021-12-02 20:24:59
(If you want to see what I look like, you can find my picture on the AoPS website somewhere I think.)
KenOno 2021-12-02 20:24:59
Except I am going bald...The photo doesn't reveal...
KenOno 2021-12-02 20:25:44
Thanks for having me tonight...Super fun...
Avemaytas 2021-12-02 20:25:49
This was one of the best Math Jams ever!
DPatrick 2021-12-02 20:25:59
Thanks...glad you liked it!
dBIT 2021-12-02 20:26:07
Also this month is National Mathematics Day in India December 22 on Ramanujan's Bday
DPatrick 2021-12-02 20:26:16
That's right! Thanks for mentioning that.
DPatrick 2021-12-02 20:26:38
I think Ken is doing an event with the Museum of Math in New York which will be online -- is that correct?
DPatrick 2021-12-02 20:26:44
(I may be misremembering)
DPatrick 2021-12-02 20:27:01
(On or around Dec 22)
KenOno 2021-12-02 20:27:31
Yes, Steven Strogatz is hosting a virtual event on December 20th called "Starring Math". I will be speaking with Manjul Bhargava and director Matt Brown. Look for info online at the Museum of Math website (MoMath).
QueenRaven337 2021-12-02 20:27:51
Thank you so much for an amazing evening!
DPatrick 2021-12-02 20:28:05
Thanks everyone for coming! Have a nice evening!
KenOno 2021-12-02 20:28:14
Good night!
HonestCat 2021-12-02 20:29:16
Thank you!
DofL 2021-12-02 20:29:16
thank you so much for the wondeful oppurtunities Dr. Ono!
peterguo 2021-12-02 20:29:16
good math jam
Kai_Zhao 2021-12-02 20:29:16
bye



.
P3Tan 2021-12-02 20:29:16
Have GREAT night ya'll! :D
horse869 2021-12-02 20:29:16
Thank you :D
HappyNarwhal 2021-12-02 20:29:16
Bye!
yashraj31 2021-12-02 20:29:16
bye!

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