The Spirit of Ramanujan
Go back to the Math Jam ArchiveAoPS instructor David Patrick will discuss the Spirit of Ramanujan Talent Initiative. We will discuss Ramanujan's life and some of the mathematics that he produced, and we will discuss the SoR program and how to apply. AoPS is a partner of SoR in 2020-21. We will be joined by Professor Ken Ono of the University of Virginia, who is the Director of the SoR program and was an associate producer and mathematical consultant for The Man Who Knew Infinity, a feature film about Ramanujan starring Dev Patel.
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Facilitator: Dave Patrick
Welcome to the 2021-22 Spirit of Ramanujan Math Jam! We'll get started in about 5 minutes.
cool, is it about the movie or the organization/scholarship?
We'll mention the movie, but it's mostly about Ramanujan himself, some of the math he did, and we'll talk about the scholarship program at the end.
Let me guess DPatrick David Patrick?
Yep, that's me!
why dont you host the math jam on his birthday
its in like less than a month
True...I think there will be other events around his birthday though!
This was a good night on our schedule and on our special guest's schedule.
Special guest?
who's the guest?
You'll find out in a minute or two!
ken ono?
Let me guess, the guest is KenOno?
Good deducing. I'll introduce him properly in a minute or so.
Time to get started!
Welcome to the 2021-22 Spirit of Ramanujan Math Jam!
I'm Dave Patrick, and I'll be leading our discussion tonight. Many of you know me from around AoPS: I've taught dozens of AoPS classes over the past 17 years, and I've written or co-written a few of our textbooks.
I'm pleased to have a very special guest here with us tonight. Ken Ono (KenOno) is the Thomas Jefferson Professor and Chair of the Department of Mathematics at the University of Virginia.
Hi everyone!
Ken is also the Director of the "Spirit of Ramanujan" project, with which AoPS is a partner, and which we'll be talking about tonight.
So happy to be here in AoPs world.
Before we get started I would like to take a moment to explain our virtual classroom procedures to those who have not previously participated in a Math Jam or one of our online classes.
The classroom is moderated, meaning that students can type into the classroom, but these comments will not go directly into the room. These comments go to the moderators, who may choose to share your comments with the room, or to respond to them privately if we can.
This helps keep the discussion organized and on track. This also means that only well-written comments are likely to be dropped into the classroom, so please take time writing responses that are complete and easy to read.
Today we also have a teaching assistant: Tudor Sarpe (Snakes).
Tudor first joined AoPS in 2015, though he has been browsing the AoPS contest collections and forums since 2012. Tudor is from Moldova, a small country in Eastern Europe that too few people know about. During High School, he has been highly involved in mathematics and science olympiads. He has won top places at national maths, biology, physics and chemistry olympiads, has a couple bronze medals from the Balkan Mathematical Olympiad, and has been on the IMO team.
Hi, everyone
Snakes is here to try to answer any questions that you have, and Ken and I will also be answering questions at the end. We may have a lot of students here tonight, so please be patient! We may not be able to get to every question.
Tonight, we're going to talk about the life and mathematics of Srinivasa Ramanujan.
And we'll be talking about a project called "Spirit of Ramanujan" that Ken Ono founded, the goal of which is to help find and nurture future mathematical and scientific talent.
But first, let's talk about Ramanujan himself.
Anybody know about him?
My dad said he could do complex math problems in his head and he didn't go to a universinty or anything
the most famous Indian mathematician.
yes he found a fraction that is better than 22/7 for pi
yes, he is a famous indian mathmaticean
I know the story about the taxi
He only lived for 33 years According to the post stamp
He was born in 1887 and died in 1920
Lots of knowledgeable folks out tonight.
As you may know, there was recently (2015) a motion picture about Ramanujan's life titled The Man Who Knew Infinity, starring Dev Patel and Jeremy Irons. The film is based on a biography of the same title written in 1991 by Robert Kanigel.
Our guest Ken Ono was one of the mathematical consultants on the film.
Did anybody here see the movie?
I did it was good
I saw the trailer
I didn't but now I want to
Yes I have seen the movie
No, but I want to now!
Unfortunately as of right now it does not appear to be available for free on any streaming service in the U.S.
It is available for rent for $2.99 on a bunch of different sites.
Ramanujan was born in Erode, India in 1887. He grew up relatively poor and worked as a clerk. But from an early age he clearly had a love and aptitude for mathematics.
By age 11 he was the mathematical equal of university students who were boarding in his family home. He was able to continue his advanced study of math by reading as many books as he could get his hands on. He also, around age 15, discovered on his own how to solve a quartic equation.
(We'll talk more about this in a few minutes when we start talking about Ramanujan's mathematical achievements. And don't worry if you don't know what "quartic equation" means -- I'll explain that too!)
but how did he get so good with no training. he can't just wake up and know everything
Well, he was fortunate in that he had access to lots of books. And he was a really hard worker!
A particular book that furthered his study was A Synopsis of Elementary Results in Pure and Applied Mathematics by G.S. Carr, that Ramanujan obtained in 1903 at age 16. This book was written in 1886. It contained over 5000 theorems and was an attempt to summarize all the "basic" mathematics known at the time. (Last time I checked, you can find it in Google Books!) Ramanujan read and studied it in great detail and it formed the foundation of his mathematical thought.
Ramanujan spent so much time on mathematics that he generally did poorly in other subjects in school, and as such failed to graduate from university. He unfortunately also suffered from various illness (much of which were probably made worse due to poverty, and to the lack of "modern" medicine in India at the time), which also interfered with his formal studies.
did he write any books?
Indeed he wrote a lot!
He started publishing papers containing his original work in India, small articles at first, but eventually his first "full" paper titled "Some Properties of Bernoulli's Numbers" in 1911 in the Journal of the Indian Mathematical Society. This paper, in particular, started establishing Ramanujan's reputation as a mathematical genius in India.
But, even though his mathematical talent was becoming acknowledged within India, he had trouble finding employment as a mathematician because of his lack of a formal university degree. Instead, he had to work as a clerk for low pay and rely on the additional financial support of others in the Indian mathematics community.
Anybody know what changed for him in 1913?
(If you saw the movie you probably know)
He wrote a letter to Hardy
he meta famous mathematician I believe
Did he gain an opportunity of some sort?
He met Hardy
he met G.H Hardy? (did not see the movie)
He worked with GH hardy
Right! A major turning point in Ramanujan's life was his writing a letter to the prominent British mathematician G. H. Hardy in January 1913. His letter began:
I have had no university education but I have undergone the ordinary school course. After leaving school I have been employing the spare time at my disposal to work at mathematics. I have not trodden through the conventional regular course which is followed in a university course, but I am striking out a new path for myself. I have made a special investigation of divergent series in general and the results I get are termed by the local mathematicians as 'startling'.
Enclosed with the letter was pages of Ramanujan's work -- he was hoping that Hardy would be able to mentor him and help him get his work improved and published to the wider world. He had written to other mathematicians in Britain, who had basically ignored his letters.
But Hardy took the letter seriously. Although a lot of the work was unproved and was poorly written, it was clear to Hardy that there was a lot of really good math in Ramanujan's letter! Hardy started a professional relationship with Ramanujan and was able to provide financial support.
David, you type really fast!!!
Magic.
cntrl C/V?
It is possible I may have written some of this beforehand...
Anyway...In 1914, Hardy arranged for Ramanujan to be able to travel and visit Trinity College at Cambridge University in England.
Any idea how long it took Ramanujan to travel from India to London? Remember, this was slightly over 100 years ago!
a month or 2
like a few weeks possibly
a month?
3 weeks?
a month? or maybe 2 weeks?
3 weeks?
These are all pretty close. It took 27 days.
Ramanujan left India on March 17, 1914 by boat, and arrived in London on April 14.
This began a 5-year collaboration with Hardy that produced many important mathematical results. Also, Ramanujan was finally able to finish his formal education, and graduated from Cambridge with the equivalent of a Ph.D. in 1916.
in 2 years?!
He had most of the knowledge already -- what the university did mostly was just make the degree official.
With financial stability and a group of peers that respected his work, Ramanujan was able to professionally thrive in England. Many honors followed including perhaps the most prestigious: in 1918 he was elected a Fellow of the Royal Society, probably the highest honor that can be given for science in Britain. Ramanujan was only the second Indian so elected, and one of the youngest at age 31.
Did he ever go back to India?
Yes: In early 1919, World War I was over so (now age 31) he decided to return to his native India, with his reputation firmly established and his financial situation stable. The hope was that he would continue his career as a full member of India's mathematical community.
And we are still trying to figure out stuff in 3 notebooks he left behind. I've held them in my hands.
Sadly, upon returning to India, he almost immediately fell into poor health, and after about a year, he died on April 26, 1920, at an age of only 32.
he had so much to live for
I got the opportunity ti visit the Ramanujan Museum in Chennai. Heartwarming to see photos and his letters displayed
If you're interested in reading a more thorough biography of Ramanujan, there is one on the "History of Mathematics" site maintained by the University of St. Andrews, at
http://www-history.mcs.st-and.ac.uk/Biographies/Ramanujan.html
The quotes that I've used above are from this page.
Nice dBit.
As an aside, this website is a great resource: it has biographies of over 3,000 mathematicians spanning over 35 centuries, from Ahmes (1680-1620 BC) to Mirzakhani (1977-2017), and includes many living mathematicians as well.
Now let's talk about some the mathematics that Ramanujan studied.
Ramanujan did a lot of mathematics in his relatively short life, and a great deal of it was quite advanced. Way too advanced for us to talk about here! But there are some objects of his study that we can discuss tonight.
First, I mentioned earlier that one of Ramanujan's earliest advanced studies was, in his early teen years, his study of solutions to quartic and quintic equations.
To start, many of you already know how to solve quadratic equations, which is an equation involving a polynomial of degree 2. In particular, how can we solve $ax^2 + bx + c = 0$?
quadratic formula
quadratic formula
quadratic formula
Comeplete the square
Factoring, complete the square, or quadratic formula
quadratic formula? complete the square? factor?
Certainly there are many different methods!
But one that always works is to use the well-known quadratic formula: $$x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$$
It is pretty straightforward to prove that this always works, using basic algebra. (We prove it in AoPS's Introduction to Algebra textbook and classes.)
I prefer completing the square
completing the square is so underrated
I agree!
The next step up is solving the cubic equation $ax^3 + bx^2 + cx + d = 0$.
But, those types of formulas has to be pretty long if applied to cubic, quartic, quintic etc.
Indeed -- there is a formula for solving this as well, but it's a lot more complicated.
Nice QueenRaven337.
If we set
$$\begin{array}{rcl}
p &=& -\frac{b}{3a} \\
q &=& p^3 + \frac{bc-3ad}{6a^2} \\
r &=& \frac{c}{3a}
\end{array}$$
then we get
$$x = \sqrt[3]{q + \sqrt{q^2 + (r-p^2)^3}} + \sqrt[3]{q - \sqrt{q^2 + (r-p^2)^3}} + p.$$
wow
woah
Yeah. Most people don't bother to ever learn this formula nowadays: it's way too complicated to accurately memorize. (I certainly don't have it memorized -- I looked it up.)
how would you go about proving it?
It's pretty complicated -- way too complicated to quickly discuss tonight I'm afraid.
But it's been around a while. This formula, and other similar formulas for solving cubics, were discovered in the 1500s. Ramanujan would have learned this in his early teens.
What Ramanujan then undertook, and eventually successfully solved himself, was solving the quartic equation $ax^4 + bx^3 + cx^2 + dx + e = 0$.
oh no...
wow
I'm not even going to write the formula down -- it would take way way too much space.
You can find it here if you're curious: https://commons.wikimedia.org/wiki/File:Quartic_Formula.svg
(Basically just look for it on Wikipedia)
It's possible that Ramanujan thought that he had discovered something new. He almost certainly didn't know that the quartic had also been solved in the 1500s.
But it is an extremely complicated formula, and it's amazing that Ramanujan was able to discover it, essentially working on his own, at age 15.
You wern't kidding about taking too much space
I know, right?
would the quintic be even longer
Yeah, Ramanujan attempted to solve the quintic equation:
$$ ax^5 + bx^4 + cx^3 + dx^2 + ex + f = 0 $$
Quintic doesn't exist
there is no quintic formula
I don't think you can solve the quintic equation...
The quintic formula doesn't exist.
He did not have success.
That's because in the early 1800s, the mathematicians Ruffini and Abel actually proved that a solution was impossible! That is, there is no possible formula (no matter how complicated) that can be used to plug in the coefficients of a quintic and output a solution. (Ruffini first came up with the result in 1799, but his proof was incomplete. Abel completed the proof in 1824.)
A little later in the 1800s, the mathematician Galois developed a new branch of mathematics (that today is called Galois theory) that provided a more elegant proof that there is no formula to solve the quintic. It's part of a branch of mathematics called field theory, which you typically first learn about in an undergraduate abstract algebra course. (Or in AoPS's Group Theory course!)
But Ramanujan probably didn't know any of this at the time. And more importantly, he didn't let his lack of success in this particular problem deter him from his continued pursuit of mathematics.
That's a good lesson for us all -- a lot of problems are hard. We may not be able to solve them. But that shouldn't deter us from trying! We often learn a lot from our attempts to solve problems, even if we don't come up with the solution we want.
So on to something else...someone mentioned a taxi a little bit eariler...
I actually took 20 years to solve a problem.
Indeed, that's not all that unusual for professional mathematicians!
I mentioned the taxi
One of the most famous anecdotes regarding Ramanujan occurred when Hardy was visiting Ramanujan in the hospital during one of his many illnesses.
Wasn't there an interesting number on the top of a taxi or something that made Ramanujan think?
yes thr taxicab numbers
That's right -- Hardy recalled telling Ramanujan that he traveled to the hospital in taxicab number $1729$, and was disappointed that the cab number was so dull. Ramanujan immediately replied that on the contrary, $1729$ was a very interesting number. Do you know why?
Sum of 2 cubes in 2 different ways
it's the sum of two cubes or smething
it was the smallest number that can be written as the sum of two cubes in two different ways
$1729$ is the smallest number that can be written as a sum of two positive cubes in two different ways! Can you find them?
Nice guys! It is also my license plate number in Virginia.
1729 = 12^3 +1^3 = 10^3 + 9^3
10^3+9^3 and 12^3+1^3
1729=$12^3+1^3=10^3+9^3$
10^3+9^3 and 12^3+1^3
1000 and 729 is one
$1^3+12^3=10^3+9^3=1729$
1000 + 729 and 1728 + 1
Nice!
$1729 = 1^3 + 12^3 = 1 + 1728$
$1729 = 9^3 + 10^3 = 729 + 1000$
For this reason, $1729$ is called the 2nd taxicab number. It's also sometimes called the Hardy-Ramanujan number.
What's the first?
The first is $2 = 1^3 + 1^3$. It's the smallest number that can be written as a sum of two positive cubes in one way.
Then, the 3rd taxicab number is the smallest number that can be written as a sum of two positive cubes in three different ways. Any guess as to how big it is? (How many digits do you think it has?)
9?
10
8
9
7 digits
x*10^8 or something
Maybe 7 digits?
You're in the right ballpark.
It's the 8-digit number $87{,}539{,}319$, which is $167^3 + 436^3 = 228^3 + 423^3 = 255^3 + 414^3$.
It's likely that this was first discovered as recently as 1957.
so the 4th would be the smallest number that can be written as a sum of two positive cubes in 4 ways?
Exactly!
And more generally, the $n$th taxicab number is the smallest positive integer that can be written as a sum of two positive cubes in $n$ different ways.
What about the next one? Was that found?
whats the highest taxi cab number found?
As of right now, the first 6 taxicab numbers are known:
$2$
$1729$
$87539319$
$6963472309248$
$48988659276962496$
$24153319581254312065344$
how do u calculate the nth taxikab number?
what is the 10th?
Nobody knows! (Yet!)
computers could probably find more, right?
Those are some big numbers
Yeah...these are big numbers even for computers.
The 6th taxicab number was only discovered by computer search in 2008.
how many digits do you think the seventh taxicab number would have
Great questions....This is about elliptic curves...and is closely related to the $1 million dollar prize problem.
Birch and Swinnerton-Dyer Conjecture.
It is known that $24885189317885898975235988544$ can be written as a sum of two perfect cubes in $7$ different ways. So the 7th taxicab number is at most this number.
But we don't know if this is actually the 7th taxicab number, because there might be a smaller number that works that we haven't found yet.
And as Ken mentions, this is not just fun and games. This is tied to some really important unanswered questions in mathematics!
Just recently in 2015, our guest Ken Ono and my AoPS colleague Sarah Trebat-Leder wrote a paper titled The 1729 K3 Surface which tied Ramanujan's observation about the number 1729 to some important curves and surfaces in the modern field of algebraic geometry.
And String theory...and quantum gravity.
Mathematics is connected in so many interesting and mysterious ways.
One more fun note about taxicab numbers: How many people here are fans of the TV show Futurama?
me!!
It's a somewhat older show by the same people that created The Simpsons.
Apparently the creators of Futurama are big fans of taxicab numbers.
In particular, the number $1729$ is hidden in several episodes. It's the registration number of the Planet Express ship on the show, for one thing.
Image from mathworld.wolfram.com
And in one scene someone hails a taxi. Can you make out the number on the cab's roof?
Image from Gawker Media
the 3rd taxicab number
87539319
87539319?
87539319
its the third taxicab nimber
81539319
875399319
It's hard to make out, but it's the 3rd taxicab number $87539319$.
A little joke for those in the know.
So, it may not surprise you to learn that Futurama's head writer did math contests in high school and has a degree in physics from Harvard!
Wow!
oo
Finally for tonight's math, let's talk about partitions.
A partition is a way a writing a positive integer as a sum of positive integers, where the order of the numbers in the sum doesn't matter.
For example, all of the partitions of $3$ are:
$3$
$2+1$
$1+1+1$
(We don't list $1+2$ separately because the order of the terms doesn't matter. We also consider the "sum" $3$ as a partition of $3$.)
One classic mathematical problem is to count the number of partitions of some number.
For example, how many partitions of $6$ are there?
To count them, we can try to list them.
6, 5+1, 4+2, 3+3
15, 24, 222, 114, 123, 1122, 1311, 121111, 111111
Indeed, if we were careful and systematic about it, we could end up with the entire list:
$6$
$5+1$
$4+2$
$4+1+1$
$3+3$
$3+2+1$
$3+1+1+1$
$2+2+2$
$2+2+1+1$
$2+1+1+1+1$
$1+1+1+1+1+1$
11
11?
11
Looks like there are 11 partitions of $6$.
is there a formula for this for a question like how many partitions of n are there
An excellent question!
Hardy and Ramanujan asked the same question!
By brute force listing them, we could make a table of the number of partitions of the first 10 positive integers:
$$\begin{array}{r|l}
n & \text{number of partitions of $n$} \\ \hline
1 & 1 \\
2 & 2 \\
3 & 3 \\
4 & 5 \\
5 & 7 \\
6 & 11 \\
7 & 15 \\
8 & 22 \\
9 & 30 \\
10 & 42
\end{array}$$
The number of partitions of $n$ gets big pretty quick. For example, do you have a rough guess for the number of partitions of $100$?
a lot.
Indeed.
over 190 million
Yeah, it gets big quickly.
Nice guess.
It turns out that there are $190{,}569{,}292$ different partitions of $100$.
is it exponential?
It does seem to be growing super-fast.
Ramanujan and Hardy wondered if they could come up with a formula for the number of partitions of $n$.
They partially succeeded. They didn't come up with an exact formula, but they did come up with a formula that provides a good approximation.
Their formula, today known as the Hardy-Ramanujan formula, is
$$p(n) \sim \frac{1}{4n\sqrt3}\exp\left(\pi\sqrt{\frac{2n}{3}}\right).$$
In the formula $\exp(x)$ is an alternative way of writing $e^x$, where $e = 2.718281828\ldots$ is the Euler number.
Using this formula, $p(100) \sim 199{,}280{,}893$. That's not too far off the exact answer that I showed you a moment ago.
what is the p at the beginning
Sorry, I should have said that. $p(n)$ is our notation for the number of partitions of $n$.
few hundred thousand off. not much
The key is that the percentage error that the formula is off by gets smaller and smaller as $n$ grows large.
For instance, we see that for $n=100$ the formula is a little less than $9$ million too high. That seems like a lot, but it's less than $5\%$ higher than the actual count.
If we go to $n=1000$, the actual count is about $2.406 \cdot 10^{31}$ and the formula gives $2.440 \cdot 10^{31}$. The formula is only off by about $1.5\%$.
At $n=10000$ the actual count is about $3.617 \cdot 10^{106}$ (that's more than a googol!) and the formula gives about $3.633 \cdot 10^{106}$. The formula is only off by about $0.5\%$.
and what is the ~ symbol
That indicates that's it's not an exact formula -- it gives an approximation.
Wait, how does pi show up here?
That's a great question.
It turns out that $\pi$ shows up in number theory a lot.
As I said before...a lot of math is connected in very surprising ways!
But you'll have to learn some more advanced math before we can explain exactly why this happens with $\pi$.
Ramanujan studied partitions of integers quite a bit and produced a lot of results. There are a lot of open questions about partitions that are still studied to this day. Indeed, this is one of the areas of study of our guest Professor Ken Ono, and a lot of his work builds on work first started by Ramanujan nearly 100 years ago.
Yup...I still like to add and count.
So that seems like a good note on which to transition into the Spirit of Ramanujan initiative. Here's an excerpt from an article called "Why Ramanujan Matters" written by Ken Ono and Robert Schneider:
Ramanujan matters because he represents endless curiosity and untapped potential, which we all have to believe in to proceed in the sciences. Science usually advances on the work of thousands, over generations, fine-tuning and extending the scope of understanding. But from time to time, creative fireballs like Ramanujan burst onto the scene propelling human thought forward. Yet what if Ramanujan had not reached out to, or been taken seriously by Hardy? The loss of scientific understanding is something our modern world could not absorb. He matters because science matters: curiosity and creativity drive scientific inquiry.
That's what the Spirit of Ramanujan (which I'm going to abbreviate as SoR from now on) is all about: finding young people who have the potential, with the right resources and mentorship, to contribute to humankind's knowledge like Ramanujan did.
We at AoPS are pleased that Ken asked us to be a part of this search. SoR's goals are also part of AoPS's goals: to create a broader community of aspiring mathematicians and problems solvers, to make connections between people who might not otherwise have the opportunity to contact, and to provide resources via our website to all corners of the country and of the world.
We are pleased to partner with AoPS.
Specifically, SoR provides two types of awards:
The Templeton-Ramanujan Development Awards will provide books and monetary grants to offset the costs of online resources.
The Templeton-Ramanujan Fellowships will provide monetary grants to offset the costs of enrolling in approved enrichment programs, such as summer camps.
Such as AoPS courses!
In case you're wondering...the "Templeton" in these names is the Templeton World Charity Foundation, created by the late Sir John Templeton, and which is providing the funding for SoR.
We have now supported 66 people worldwide...from 14 countries.
Indeed, 2021-22 is the 6th year of the program. About half of the students supported are from the U.S. and half from elsewhere in the world.
Two of our former winners this year won the Regeneron Science Talent Search...and also a Rhodes Scholarship.
Basically, SoR is hoping to play to role for future Ramanujans that G. H. Hardy did for the actual Ramanujan: access to resources and mentorship to nurture future mathematical and scientific talent.
To learn more about SoR, please visit the website spiritoframanujan.com. (Should be easy to remember, no?) The SoR website includes a link to the application page. You can also read brief bios of the previous winners on the website.
Please note that although awards for the 2021-22 school year will be made on a rolling basis, you should apply by April 30, 2022 in order to guarantee full consideration.
In recent years we have offered scholarships to things like AoPS courses...Canada/USA MathCamp, PROMYS, etc...
Yes, I believe that generally Ken and the foundation works with the award winners to tailor a program that's best for that person.
David is on our board...along with Fields medalist Manjul Bhargava...and others....
Yes, please apply. We seek enthusiastic creative minds...Especially if our support can make participation possible.
...and Po-Shen Loh I believe, is that right?
Ah yes...How can I forget Po-Shen...
Certainly a familiar name to many on AoPS!
who is po shen?
He is the leader of the US Team for the International Math Olympiad.
(Among other things!)
That's all we have for tonight...we can try to answer some questions for a little while if you have any. There's also lots of info on the SoR website, along with contact info if you'd like to follow up.
spiritoframanujan.com
To repeat...please visit spiritoframanujan.com
Can't repeat it enough!
when is the optimal time to apply for SoR? what qualifications do we need for it?
Anytime between now and April 30 will guarantee full consideration.
The info you'll need to apply is on the website.
We have made awards to students as young as 8-9....
Oh KevinOno you face revealed!
Yes, if you want to see what Ken looks like, go to the SoR website.
(If you want to see what I look like, you can find my picture on the AoPS website somewhere I think.)
Except I am going bald...The photo doesn't reveal...
Thanks for having me tonight...Super fun...
This was one of the best Math Jams ever!
Thanks...glad you liked it!
Also this month is National Mathematics Day in India December 22 on Ramanujan's Bday
That's right! Thanks for mentioning that.
I think Ken is doing an event with the Museum of Math in New York which will be online -- is that correct?
(I may be misremembering)
(On or around Dec 22)
Yes, Steven Strogatz is hosting a virtual event on December 20th called "Starring Math". I will be speaking with Manjul Bhargava and director Matt Brown. Look for info online at the Museum of Math website (MoMath).
Thank you so much for an amazing evening!
Thanks everyone for coming! Have a nice evening!
Good night!
Thank you!
thank you so much for the wondeful oppurtunities Dr. Ono!
good math jam
bye
.
Have GREAT night ya'll!
Thank you
Bye!
bye!
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