1955 AHSME Problems/Problem 35
Three boys agree to divide a bag of marbles in the following manner. The first boy takes one more than half the marbles. The second takes a third of the number remaining. The third boy finds that he is left with twice as many marbles as the second boy. The original number of marbles:
Solution
The line that represents the marbles is split into three sections: . Since the amount of marbles each boy relies on the variable , which cannot be solved for, the original amount of marbles .
See Also
Go to the rest of the 1955 AHSME Problems
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