1956 AHSME Problems/Problem 25
Problem 25
The sum of all numbers of the form , where takes on integral values from to is:
Solution
The sum of the odd integers from to is . However, in this problem, the sum is instead , starting at rather than . To rewrite this, we note that is less than for every we add, so for 's, we subtract , giving us ,which factors as .
See Also
1956 AHSME (Problems • Answer Key • Resources) | ||
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Followed by Problem 26 | |
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