1960 AHSME Problems/Problem 26
Problem
Find the set of -values satisfying the inequality . [The symbol means if is positive, if is negative, if is zero. The notation means that a can have any value between and , excluding and . ]
Solutions
Solution 1
Break up the absolute value into two cases.
For the first case, let , so is positive. That means (for ) For the second case, let , so is negative. That means (for )
Combine both cases to get , which is answer choice .
Solution 2
Another way to solve this is to graph and . The solution is the areas on the graph where the y-values of are lower than . From the graph, , so the answer is .
See Also
1960 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 25 |
Followed by Problem 27 | |
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All AHSME Problems and Solutions |