1961 IMO Problems/Problem 3
Problem
Solve the equation
where is a given positive integer.
Solution
Since , we cannot have solutions with and . Nor can we have solutions with , because the sign is wrong. So the only solutions have or , and these are: multiple of , and even; even multiple of and odd; = even multiple of and odd.
1961 IMO (Problems) • Resources | ||
Preceded by Problem 2 |
1 • 2 • 3 • 4 • 5 • 6 | Followed by Problem 4 |
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