1966 AHSME Problems/Problem 6
Problem
is the diameter of a circle centered at . is a point on the circle such that angle is . If the diameter of the circle is inches, the length of chord , expressed in inches, is:
Solution
We see that is half the measure of , so . That makes a triangle and sidelength equal to .
See also
1966 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
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