1971 AHSME Problems/Problem 29
Problem
Given the progression . The least positive integer such that the product of the first terms of the progression exceeds is
Solution
By the rules of exponents, the product of the first terms of the sequence equals . From here, we can set up the equation , which simplifies to , or . By the formula for triangular numbers, . Thus, , or . Because , only makes the product equal . However, we have to strictly exceed , so our answer is
See Also
1971 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 28 |
Followed by Problem 30 | |
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