1973 AHSME Problems/Problem 9
Problem
In with right angle at , altitude and median trisect the right angle. If the area of is , then the area of is
Solution
Draw diagram as shown (note that and can be interchanged, but it doesn’t change the solution).
Note that because is a median, . Also, by ASA Congruency, , so . That means , and since and share an altitude, .
See Also
1973 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 8 |
Followed by Problem 10 | |
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