1977 AHSME Problems/Problem 3

Problem 3

A man has $2.73 in pennies, nickels, dimes, quarters and half dollars. If he has an equal number of coins of each kind, then the total number of coins he has is

$\text{(A)}\ 3 \qquad \text{(B)}\ 5 \qquad \text{(C)}\ 9 \qquad \text{(D)}\ 10 \qquad \text{(E)}\ 15$

Solution

Solution by e_power_pi_times_i

Denote the number of pennies, nickels, dimes, quarters, and half-dollars by $x$ . Then $x+5x+10x+25x+50x = 273$ , and $x = 3$ . The total amount of coins is $5x$ , which is $\textbf{\text{(E)}}\ 15$ .

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1977 AHSME Problems/Problem 3

Problem 3

Solution