1982 AHSME Problems/Problem 2

Problem

If a number eight times as large as $x$ is increased by two, then one fourth of the result equals

$\text{(A)} \ 2x + \frac{1}{2} \qquad \text{(B)} \ x + \frac{1}{2} \qquad \text{(C)} \ 2x+2 \qquad \text{(D)}\ 2x+4 \qquad \text{(E)}\ 2x+16$

Solution

The number $8$ times as large as $x$ will be $8x$ , and $8x$ increased by two will give $8x+2$ . Hence finally, the answer is $\frac{1}{4}(8x+2) = \boxed{\text{(A)}\ 2x + \frac{1}{2}}$ .

1982 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 1	Followed by Problem 3
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1982 AHSME Problems/Problem 2

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