1984 USAMO Problems/Problem 4
A difficult mathematical competition consisted of a Part I and a Part II with a combined total of problems. Each contestant solved problems altogether. For each pair of problems, there were exactly two contestants who solved both of them. Prove that there was a contestant who, in Part I, solved either no problems or at least four problems.
This problem needs a solution. If you have a solution for it, please help us out by.
|1984 USAMO (Problems • Resources)|
|1 • 2 • 3 • 4 • 5|
|All USAMO Problems and Solutions|