1987 AHSME Problems/Problem 9
Problem
The first four terms of an arithmetic sequence are . The ratio of to is
Solution
To get from the second term to the fourth term, we add lots of the common difference, so if the common difference is , we have . Thus the sequence is , so the ratio is , which is answer .
See also
1987 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 8 |
Followed by Problem 10 | |
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