1987 IMO Problems/Problem 6
Problem
Let be an integer greater than or equal to 2. Prove that if is prime for all integers such that , then is prime for all integers such that .
Solution
First observe that if is relatively prime to , , , , then is relatively prime to any number less than . Since if , then we can choose some to make lies in range , so is relatively prime to . Hence is also. If we also have , then we can conclude that is a prime. Since there must be a factor of less than .
Let where , so is the greatest integer less than or equal to .(to see this, just let , then we can write , so ).
Assume that is prime for . We show that is prime for . By our observation above, it is sufficient to show that and is relatively prime to all of . We have . Since , we have , and . Hence . Now if has a factor which divides int the range to , then so does which have the form with in range to .
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