1989 AHSME Problems/Problem 11
Problem
Let , , , and be positive integers with , , and . If , the largest possible value for is
Solution
Each of these integers is bounded above by the next one.
- , so the maximum is .
- , so the maximum is .
- , so the maximum is .
- , so the maximum is .
Note that the statement is true, but does not specify the distances between each pair of values.
See also
1989 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 10 |
Followed by Problem 12 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.