1993 AHSME Problems/Problem 19
Problem
How many ordered pairs of positive integers are solutions to
Solution
Multiply both sides by to clear the denominator. Moving all the terms to the right hand side, the equation becomes . Adding 8 to both sides allows us to factor the equation as follows: . Since the problem only wants integer pairs , the pairs are given by the factors of 8, which are 1,2,4, and 8. This results in four pairs, and , which is answer .
See also
1993 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 18 |
Followed by Problem 20 | |
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