2001 OIM Problems/Problem 1

Problem

We say that a natural number is "çharrúa" if it simultaneously satisfies the following conditions:

• All digits of are greater than 1.

• Whenever four digits of are multiplied, a divisor of is obtained.

Show that for each natural number there is a çharrúa number with more than digits.

~translated into English by Tomas Diaz. ~orders@tomasdiaz.com

Solution

This problem needs a solution. If you have a solution for it, please help us out by adding it.