2002 AMC 10P Problems/Problem 2
Contents
[hide]Problem 2
The sum of eleven consecutive integers is What is the smallest of these integers?
Solution 1
We can use the sum of an arithmetic series to solve this problem.
Let the first integer equal The last integer in this string will be Plugging in and into we get:
Thus, our answer is
Solution 2
We can directly add everything up since is so little.
Similar to the first solution, let the first integer equal The last integer in this string will be
Thus, our answer is
See Also
2002 AMC 10P (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
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