2005 PMWC Problems/Problem I14

Solution

From the given, we have the equations

\[3g = 6b \Longrightarrow g = 2b\] \[2y = 5b \Longrightarrow y = \frac{5}{2}b\] \[4w = 6b \Longrightarrow w = \frac{3}{2}b\]

Substuting gives us $4g + 2y + 2w = 4(2b) + 2\left(\frac{5}{2}b\right) + 2\left(\frac{3}{2}b\right) = 16b$, and our answer is 16.

See also

2005 PMWC (Problems)
Preceded by
Problem I13
Followed by
Problem I15
I: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
T: 1 2 3 4 5 6 7 8 9 10
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