2008 Mock ARML 2 Problems/Problem 1
Problem
is a convex quadrilateral such that , , , and . Given that , find the area of .
Solution
Note that . Thus, if we let be the intersection of the extensions of and , it follows that is a right triangle. Immediately we notice that is a and that is a ; otherwise we can determine these lengths through the Pythagorean Theorem.
The answer is .
See also
2008 Mock ARML 2 (Problems, Source) | ||
Preceded by First question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 |