2009 AMC 10B Problems/Problem 9
Contents
[hide]Problem
Segment and intersect at , as shown, , and . What is the degree measure of ?
Solution
is isosceles, hence .
The sum of internal angles of can now be expressed as , hence , and each of the other two angles is .
Now we know that .
Finally, is isosceles, hence each of the two remaining angles ( and ) is equal to .
Video Solution
~savannahsolver
See Also
2009 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 8 |
Followed by Problem 10 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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