2012 CEMC Gauss (Grade 7) Problems/Problem 8

Problem

Bailey scores on six of her eight shots. The percentage of shots that she does not score on is

$\text{ (A) }\ 2 \qquad\text{ (B) }\ 40 \qquad\text{ (C) }\ 10 \qquad\text{ (D) }\ 20 \qquad\text{ (E) }\ 25$

Solution 1

Solving for the percentage of shots that she scored on, we have

$\frac{6}{8} = 0.75 = 75\%$

The percentage of shots that she scored on added to the percentage of shots that she didn't score should result in $100\%$ . Letting $p$ be the percentage of shots that she didn't score, we have:

$p + 75\% = 100\%$

$p = 25\%$

Thus, the answer is $\boxed {\textbf {(E) } 25}$ .

Solution 2

Let $m$ be the number of shots that she missed. Since she scored on $6$ shots out of $8$ shots, we have:

$m + 6 = 8$

$m = 2$ .

Solving for the percentage of shots that she missed based on the calculated value of m, we have:

$\frac{m}{8} = \frac{2}{8} = 0.25 = 25\%$

Thus, the answer is $\boxed {\textbf {(E) } 25}$ .

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2012 CEMC Gauss (Grade 7) Problems/Problem 8

Problem

Solution 1

Solution 2