2012 OIM Problems/Problem 2

Problem

A positive integer is bisummed if it can be written as the sum of two integers positive numbers that have the same sum of their digits. For example, 2012 is bisumed because $2012 = 2005 + 7$ and both 2005 and 7 have their digit sum equal to 7. Find all the positive integers that are not 'bisummed.

~translated into English by Tomas Diaz. ~orders@tomasdiaz.com

Solution

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See also

OIM Problems and Solutions