2013 AMC 8 Problems/Problem 17
Contents
Problem
The sum of six consecutive positive integers is 2013. What is the largest of these six integers?
Solution 1
The mean of these numbers is . Therefore the numbers are , so the answer is
Solution 2
Let the number be . Then our desired number is .
Our integers are , so we have that .
Solution 3
Let the first term be . Our integers are . We have,
Solution 4
Since there are numbers, we divide by to find the mean of the numbers. . Then, (the fourth number). Fifth: ; Sixth: .
Solution 5
Let the number be . Then our list is: . Simplifying this gets you , which means that
Video Solution
https://youtu.be/E7DZ1oILqE0 ~savannahsolver
See Also
2013 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 16 |
Followed by Problem 18 | |
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