2015 AMC 12A Problems/Problem 13
Contents
Problem
A league with 12 teams holds a round-robin tournament, with each team playing every other team exactly once. Games either end with one team victorious or else end in a draw. A team scores 2 points for every game it wins and 1 point for every game it draws. Which of the following is NOT a true statement about the list of 12 scores?
Solution 1
We can eliminate answer choices and because there are an even number of scores, so if one is false, the other must be false too. Answer choice must be true since every team plays every other team, so it is impossible for two teams to lose every game. Answer choice must be true since each game gives out a total of two points, and there are games, for a total of points. Answer choice is false. If everyone draws each of their 11 games, then every team will tie for first place with 11 points each.
Solution 2
We will proceed by process of elimination:
: We know that this must be true, since any tied results in a 1 point (which is odd) for both teams. Hence, there must be 0 or a positive even number of odd scores.
: This is true too, because each non-tie generates 2 points for the winner, and 0 points for the loser, which are both even scores. Hence, there must be 0 or a positive even number of even scores as well.
: This must be true since every team plays every other team, so it is impossible for two teams to lose every game.
: This is true as well. Since any game gives out a net total of two points, and there are games, there are a total of points for any round-robin tournament.
Therefore, answer choice is false. If everyone ties, every team will be tied for the first place with 11 points each.
~xHypotenuse
See Also
2015 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 12 |
Followed by Problem 14 |
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All AMC 12 Problems and Solutions |