2019 AMC 12A Problems/Problem 2
Contents
Problem
Suppose is of . What percent of is ?
Solution 1
Since , that means . We multiply by to get a term, yielding , and is of .
Solution 2
Without loss of generality, let . Then, we have and . Thus, , so is of . Hence the answer is .
Solution 3 (similar to Solution 1)
As before, . Multiply by 2 to obtain . Since , the answer is .
Solution 4 (similar to Solution 2)
Without loss of generality, let . Then, we have and . This gives , so is of , so the answer is .
See Also
2019 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 1 |
Followed by Problem 3 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.