2021 JMPSC Invitationals Problems/Problem 9
Problem
In , let be on such that . If , , and , find
Solution 1
From the fact that and we find that is a right triangle with a right angle at thus by the Pythagorean Theorem we obtain ~samrocksnature
Solution 2 (Stewart's Theorem)
Note that , which means and . Now, Stewart's Theorem dictates , yielding ~Geometry285
See also
- Other 2021 JMPSC Invitationals Problems
- 2021 JMPSC Invitationals Answer Key
- All JMPSC Problems and Solutions
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