2021 JMPSC Problems/Problem 1

Problem

Compute $\left(\frac{1}{3}+\frac{1}{6}+\frac{1}{9}\right)(3+6+9)$ .

Solution

Solving the right side gives $3 + 6 + 9 = 18$ . Distributing into the left side gives $\frac{18}{3}+\frac{18}{6}+\frac{18}{9}$ , so the answer is $6 + 3 + 2 = \boxed{11}$ .

Page

Toolbox

Search

2021 JMPSC Problems/Problem 1

Problem

Solution