AoPS Wiki talk:Problem of the Day/September 13, 2011
Since , we can use the difference of cubes factorization: and since we are given that the original number has at most 2 prime factors, both of these must be prime. The larger is .
Since , we can use the difference of cubes factorization: and since we are given that the original number has at most 2 prime factors, both of these must be prime. The larger is .
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