Gauss Grade 7 Year 2011 Problem 1

The value of $5 + 4 - 3 + 2 - 1$ is $\textbf {(A) 0} \ \ \ \textbf {(B) 5} \ \ \ \textbf {(C) 3} \ \ \ \textbf {(D) 3} \ \ \ \textbf {(E) 7}$

$5 + 4 - 3 + 2 - 1 = 9 - 3 + 2 - 1 = 6 + 1 = \boxed {\textbf {(E) 7}}$

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