MIE 2015/Day 1/Problem 2
Problem 2
The polynomial has real roots , and . Thus the value of the sum of is:
(a)
(b)
(c)
(d)
(e)
Solution
By Girard's relations (also called Vieta's formulas or Newton's identities),
The polynomial has real roots , and . Thus the value of the sum of is:
(a)
(b)
(c)
(d)
(e)
By Girard's relations (also called Vieta's formulas or Newton's identities),
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