Mock AIME 1 2010 Problems/Problem 8

Solution

Once the pieces are placed, there will be $20-3(3)-2(2)-1=6$ blank spaces. So, we are simply ordering $3$ triominoes, $2$ dominoes, $1$ square, and $6$ blank spaces. That's just $\frac{12!}{3!2!6!} = 55440$ , with last three digits $\boxed{440}$ .

Page

Toolbox

Search

Mock AIME 1 2010 Problems/Problem 8

Solution