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- 20:48, 27 March 2014 (diff | hist) . . (+899) . . N 2014 AIME II Problems/Problem 12 (Created page with "Obviously, <math>A+B+C=180</math> in degrees. Note that <math>\cos{3C}=-\cos{(3A+3B)}</math>. Thus, our expression is of the form <math>\cos{3A}+\cos{3B}-\cos{(3A+3B)}=1</math>. ...")
