Search results

  • *(BorealBear) Find the last two digits of <math> 7^{81}-3^{81} </math>. ([[Euler's Totie *(BorealBear) Find the last two digits of <math> 3^{3^{3^{3}}} </math>. ([[Euler's Totie
    4 KB (569 words) - 21:34, 30 December 2024
  • ...ositive integers. What is the largest possible value of <math> x </math>? (BorealBear)
    4 KB (699 words) - 19:30, 7 October 2024
  • | 81 || BorealBear || 40 || 6968.231 || 174.206 | 125 || BorealBear || 51 || 3981.755 || 78.074
    187 KB (10,824 words) - 17:27, 3 February 2022
  • -BorealBear
    4 KB (652 words) - 09:33, 9 November 2024
  • Doing the subtraction yields <math> \boxed{\textbf{(B) }9900} </math>. -BorealBear
    7 KB (1,032 words) - 01:10, 17 July 2024
  • 2 BorealBear
    11 KB (1,044 words) - 19:27, 21 September 2024
  • ...third terms, our answer is <math> (5+5)+(7+14)=10+21=\boxed{031} </math>. -BorealBear, minor edit by Kinglogic
    7 KB (1,137 words) - 19:20, 16 January 2025
  • ...</math>, our answer is <math> \boxed{\textbf{(C) }\frac{1}{20}} </math>. -BorealBear
    12 KB (1,898 words) - 11:31, 3 November 2024
  • (BorealBear) Find the last two digits of <math> 7^{81}-3^{81} </math>. ...math>, this reduces to <math> 7^1-3^1\equiv \boxed{04}\pmod{100} </math>. -BorealBear
    272 bytes (35 words) - 16:33, 21 March 2023
  • (BorealBear) Find the last two digits of <math> 3^{3^{3^{3}}} </math>. ~BorealBear
    770 bytes (109 words) - 21:14, 15 August 2023
  • ...7+18+19+26+27+28+35=27+54+81+35=162+35=\boxed{\mathrm{(B)}\ 197} .</math> -BorealBear
    5 KB (901 words) - 17:36, 13 November 2023