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• Euler's Totient Theorem
  *(BorealBear) Find the last two digits of <math> 7^{81}-3^{81} </math>. ([[Euler's Totie *(BorealBear) Find the last two digits of <math> 3^{3^{3^{3}}} </math>. ([[Euler's Totie
  3 KB (542 words) - 17:45, 21 March 2023
• Legendre's Formula
  ...ositive integers. What is the largest possible value of <math> x </math>? (BorealBear)
  4 KB (699 words) - 17:55, 5 August 2023
• 2015 AMC 8 Problems/Problem 19
  -BorealBear
  4 KB (596 words) - 00:07, 17 May 2023
• Reaper Archives
  | 81 || BorealBear || 40 || 6968.231 || 174.206 | 125 || BorealBear || 51 || 3981.755 || 78.074
  187 KB (10,824 words) - 18:27, 3 February 2022
• 2019 AMC 8 Problems/Problem 25
  -BorealBear
  4 KB (647 words) - 04:23, 30 January 2024
• 2020 AMC 10A Problems/Problem 8
  Doing the subtraction yields <math> \boxed{\textbf{(B) }9900} </math>. -BorealBear
  6 KB (899 words) - 22:29, 20 October 2023
• Mathcounts Week/Countdown Round
  2 BorealBear
  11 KB (1,044 words) - 17:36, 11 January 2021
• 2021 AIME I Problems/Problem 5
  ...third terms, our answer is <math> (5+5)+(7+14)=10+21=\boxed{031} </math>. -BorealBear, minor edit by Kinglogic
  7 KB (1,150 words) - 03:15, 1 February 2024
• 2021 AMC 10B Problems/Problem 18
  ...</math>, our answer is <math> \boxed{\textbf{(C) }\frac{1}{20}} </math>. -BorealBear
  8 KB (1,296 words) - 17:48, 10 November 2023
• Euler's Totient Theorem Problem 1 Solution
  (BorealBear) Find the last two digits of <math> 7^{81}-3^{81} </math>. ...math>, this reduces to <math> 7^1-3^1\equiv \boxed{04}\pmod{100} </math>. -BorealBear
  272 bytes (35 words) - 17:33, 21 March 2023
• Euler's Totient Theorem Problem 2 Solution
  (BorealBear) Find the last two digits of <math> 3^{3^{3^{3}}} </math>. ~BorealBear
  770 bytes (109 words) - 22:14, 15 August 2023
• 2021 Fall AMC 10B Problems/Problem 22
  ...7+18+19+26+27+28+35=27+54+81+35=162+35=\boxed{\mathrm{(B)}\ 197} .</math> -BorealBear
  5 KB (901 words) - 18:36, 13 November 2023