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- == Problem == ...m can then be tackled by taking the cotangent of both sides of the inverse cotangent addition formula shown at the beginning.3 KB (473 words) - 11:06, 18 December 2018
- == Problem == ...>\cot{\alpha}+\cot{\beta}=\frac{c}{h}</math>, from the definition of the [[cotangent]].8 KB (1,401 words) - 20:41, 20 January 2024
- ==Problem== ...AC}</math>. Because <math>P</math> is the midpoint of <math>AM</math>, the cotangent rule applied on triangle <math>MBA</math> gives us13 KB (1,811 words) - 13:36, 1 June 2024
- ==Problem== ...\tan\frac{9\pi}{16}, \tan\frac{13\pi}{16}</math>, so the second symmetric sum of these four numbers is <math>6</math> by Vieta's. Thus, we have <cmath>\t14 KB (2,130 words) - 20:05, 27 December 2024