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• 2013 AMC 12B Problems/Problem 19
  ...the Pythagorean theorem, we end up with similar triangles <math>\triangle{DFG}</math> and <math>\triangle{DCE}</math>. Thus, <math>FG=\tfrac35x</math> an
  6 KB (1,004 words) - 22:38, 18 June 2023
• 2020 USOJMO Problems/Problem 4
  ...i - \angle FED</math>. Thus F, A, D, and E are concyclic, and <math>\angle DFG = \angle DAE = \angle DAC - \angle EAC = \angle DBC - x</math> Let this be ...FGD and statement 1 gives <cmath>\begin{align*}\angle FDG &= \pi - \angle DFG - \angle FGB \\
  6 KB (1,131 words) - 19:15, 6 October 2023
• Miquel's point
  <math>AD||GF \implies \angle ADE + \angle DFG = 180^\circ \implies \angle ADE + \angle AME = 180^\circ \implies</math>
  6 KB (976 words) - 23:10, 28 October 2023