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- ...ruent. Notice that <math>\angle{KNL}=45^\circ</math>, etc, so <math>\angle{KNM}=90^\circ</math>. So we have a square.3 KB (483 words) - 16:26, 22 June 2023
- ...= \angle KMN = 90^{\circ}</math>. Thus, <math>\triangle KOP \sim \triangle KNM</math>.11 KB (1,764 words) - 12:23, 25 November 2024
- <math>\cot \angle GNS = \tan (90 ^{\circ} - \angle GNS) = \tan \angle KNM = \tan (\angle KNQ + \angle QNM) = \frac{\tan \angle KNQ + \tan \angle QNM}17 KB (2,502 words) - 15:13, 3 November 2024