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• Isogonal conjugate
  ...l similarity centered at <math>M</math> transform triangle <math>\triangle MPE</math> to <math>\triangle MDP' \implies</math> <cmath>\angle MPE = \angle MDP', \frac {MP}{MD} = \frac {PE}{DP'} = \frac{PF}{DG} \implies</c
  54 KB (9,416 words) - 08:40, 18 April 2024