Talk:2007 AMC 10B Problems/Problem 11

Another possible solution is to plot the circle and triangle on a graph with the circle having center (0,0). Radius of circle = r distance between origin and base of triangle = a 1 + a^2 = r^2 r + a = 2sqrt(2) a = (2)sqrt(2) - r 9 - (4r)sqrt(2) = 0 r = ((9)sqrt(2))/8 πr^2 = 81π/32

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