User talk:Temperal/The Problem Solver's Resource Competition
I don't think the question is worded correctly. I haven't actually thought much about it yet, but a variable is introduced and not used, and the simply disappears from the ending condition (but the condition given is symmetric). And there are simple counter-proofs, let or some other value close to 0, and then it quickly becomes apparent that the entire denominator will approach , and the inequality will be false. Azjps (talk) 21:49, 10 October 2007 (EDT)
- Random counter-example: , , . Then the fraction becomes .
- And problem 3, the same equation is given for both circles. I'm assuming you meant for one of the radii? Azjps (talk) 18:33, 12 October 2007 (EDT)