Difference between revisions of "2019 AMC 10A Problems/Problem 1"
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== Solution == | == Solution == | ||
| − | <math>2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9 | + | <math>2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9= 1+1 = \boxed{\textbf{(C) } 2}</math>. |
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| + | ==Video Solution by Education, the Study of Everything== | ||
https://youtu.be/K8je0WYBHFc | https://youtu.be/K8je0WYBHFc | ||
| − | Education, The Study Of Everything | + | ~Education, The Study Of Everything |
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| − | == Video Solution | + | == Video Solution by WhyMath== |
https://youtu.be/Ad8WKcwZcTA | https://youtu.be/Ad8WKcwZcTA | ||
~savannahsolver | ~savannahsolver | ||
| − | == Video Solution | + | == Video Solution by T2L Academy== |
https://www.youtube.com/watch?v=OhCy9c2RTFo&list=PLbhMrFqoXXwnSCZShTPinX9ZHWjzIlQr_&index=1 | https://www.youtube.com/watch?v=OhCy9c2RTFo&list=PLbhMrFqoXXwnSCZShTPinX9ZHWjzIlQr_&index=1 | ||
Revision as of 12:54, 16 July 2024
Contents
Problem
What is the value of ![\[2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9?\]](http://latex.artofproblemsolving.com/6/7/6/67606c2b8141058216ca18ee5e71821458b74b01.png)
Solution
.
Video Solution by Education, the Study of Everything
~Education, The Study Of Everything
Video Solution by WhyMath
~savannahsolver
Video Solution by T2L Academy
https://www.youtube.com/watch?v=OhCy9c2RTFo&list=PLbhMrFqoXXwnSCZShTPinX9ZHWjzIlQr_&index=1
See Also
| 2019 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
