Difference between revisions of "2002 AMC 10P Problems/Problem 1"
(→Solution 1) |
(→Problem 1) |
||
| Line 1: | Line 1: | ||
| − | == Problem | + | == Problem == |
The ratio <math>\frac{(2^4)^8}{(4^8)^2}</math> equals | The ratio <math>\frac{(2^4)^8}{(4^8)^2}</math> equals | ||
Revision as of 18:44, 14 July 2024
Problem
The ratio 
equals
Solution 1
See also
| 2002 AMC 10P (Problems • Answer Key • Resources) | ||
| Preceded by First question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
