Difference between revisions of "1988 AJHSME Problems/Problem 6"
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==Solution== | ==Solution== | ||
Converting the [[decimal|decimals]] to [[fraction|fractions]] gives us <math>\frac{(.2)^3}{(.02)^2} =\frac{\left( \frac{1}{5}\right)^3}{\left(\frac{1}{50}\right)^2}=\frac{50^2}{5^3}=\frac{2500}{125}=20\Rightarrow \mathrm{(E)}</math>. | Converting the [[decimal|decimals]] to [[fraction|fractions]] gives us <math>\frac{(.2)^3}{(.02)^2} =\frac{\left( \frac{1}{5}\right)^3}{\left(\frac{1}{50}\right)^2}=\frac{50^2}{5^3}=\frac{2500}{125}=20\Rightarrow \mathrm{(E)}</math>. | ||
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| + | ==Solution 2== | ||
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| + | We expand <math>\frac{(0.2)^3}{(0.02)^2}</math>, and get <math>\frac{(0.2) \times (0.2) \times (0.2)}{(0.02) \times (0.02)}</math>. The two <math>0.02</math>'s "cancel" out with the two <math>0.2</math>'s, leaving the fraction as: <math>(10) \times (10) \times (0.2)</math>. Using basic calculations, we compute this expression to get <math>20\Rightarrow \mathrm{(E)}</math>. | ||
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| + | ~sakshamsethi | ||
==See Also== | ==See Also== | ||
Latest revision as of 11:04, 28 July 2020
Contents
Problem
Solution
Converting the decimals to fractions gives us 
.
Solution 2
We expand 
, and get 
. The two 
's "cancel" out with the two 
's, leaving the fraction as: 
. Using basic calculations, we compute this expression to get 
.
~sakshamsethi
See Also
| 1988 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
