Difference between revisions of "1988 AJHSME Problems/Problem 7"

Latest revision as of 14:56, 21 November 2020

$2.46\times 8.163\times (5.17+4.829)$ is closest to

$\text{(A)}\ 100 \qquad \text{(B)}\ 200 \qquad \text{(C)}\ 300 \qquad \text{(D)}\ 400 \qquad \text{(E)}\ 500$

We can round. We can make 2.46*8.163*(5.17+4.829) to 2*8*(5+5) which equals 160. 160 is closest to 200 so the answer is B. ~avamarora

1988 AJHSME (Problems • Answer Key • Resources)
Preceded by Problem 6	Followed by Problem 8
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

@@ Line 7: / Line 7: @@
 ==Solution==
-We estimate the first thing to be <math>2.5</math>, the second thing to be <math>8</math>, and the third thing to be <math>10</math>. We now have <math>2.5\cdot 8\cdot 10=25\cdot 8=200\Rightarrow \mathrm{(B)}</math>.
+We can round. We can make 2.46*8.163*(5.17+4.829) to 2*8*(5+5) which equals 160. 160 is closest to 200 so the answer is B. ~avamarora
 ==See Also==
@@ Line 13: / Line 13: @@
 {{AJHSME box|year=1988|num-b=6|num-a=8}}
 [[Category:Introductory Algebra Problems]]
+{{MAA Notice}}