Difference between revisions of "2009 AMC 8 Problems/Problem 4"
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==Solution== | ==Solution== | ||
The answer is <math>\boxed{\textbf{(B)}}</math> because the longest piece can't fit in the figure. | The answer is <math>\boxed{\textbf{(B)}}</math> because the longest piece can't fit in the figure. | ||
+ | |||
+ | == Video Solution == | ||
+ | https://youtu.be/USVVURBLaAc?t=171 | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2009|num-b=3|num-a=5}} | {{AMC8 box|year=2009|num-b=3|num-a=5}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 22:55, 28 January 2021
Contents
[hide]Problem
The five pieces shown below can be arranged to form four of the five figures shown in the choices. Which figure cannot be formed?
Solution
The answer is because the longest piece can't fit in the figure.
Video Solution
https://youtu.be/USVVURBLaAc?t=171
See Also
2009 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.