Difference between revisions of "2021 AMC 10A Problems/Problem 2"
MRENTHUSIASM (talk | contribs) |
Happykeeper (talk | contribs) |
||
Line 21: | Line 21: | ||
- pi_is_3.14 | - pi_is_3.14 | ||
+ | {{AMC10 box|year=2021|ab=A|before=Problem 1|num-a=2}} | ||
+ | {{MAA Notice}} |
Revision as of 22:20, 11 February 2021
Problem 2
Portia's high school has times as many students as Lara's high school. The two high schools have a total of
students. How many students does Portia's high school have?
Solution
The following system of equations can be formed with representing the number of students in Portia's high school and
representing the number of students in Lara's high school.
Substituting
with
we get
. Solving for
, we get
. Since we need to find
we multiply
by 3 to get
, which is
-happykeeper
Solution 2 (One Variable)
Suppose Lara's high school has students. It follows that Portia's high school has
students. We know that
or
Our answer is
~MRENTHUSIASM
Video Solution
- pi_is_3.14
2021 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.