Difference between revisions of "2021 AMC 10A Problems/Problem 24"
Firebolt360 (talk | contribs) (→Solution) |
Firebolt360 (talk | contribs) |
||
Line 12: | Line 12: | ||
~ pi_is_3.14 | ~ pi_is_3.14 | ||
+ | |||
+ | ==See also== | ||
+ | {{AMC10 box|year=2021|ab=A|num-b=23|num-a=25}} | ||
+ | {{MAA Notice}} |
Revision as of 22:22, 11 February 2021
Contents
Problem 24
The interior of a quadrilateral is bounded by the graphs of and , where a positive real number. What is the area of this region in terms of , valid for all ?
Solution
The conditions and give and or and . The slopes here are perpendicular, so the quadrilateral is a rectangle. Plug in and graph it. We quickly see that the area is , so the answer can't be or by testing the values they give (test it!). Now plug in . We see using a ruler that the sides of the rectangle are about and . So the area is about . Testing we get which is clearly less than , so it is out. Testing we get which is near our answer, so we leave it. Testing we get , way less than , so it is out. So, the only plausible answer is ~firebolt360
Video Solution by OmegaLearn (System of Equations and Shoelace Formula)
~ pi_is_3.14
See also
2021 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 23 |
Followed by Problem 25 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.